Hello,
52% of 230 = 52/100 × 230 = 0,52 × 230 = 119,6
Correct answer is E. The primary purpose of Passage 1 is to Highlight a concern.
The passage talks about spam and junk mail in our mail inbox and one has to go through it all to find out real and important mails. This spam mails and the manner they flood our mails in is concerning. This is what the passage highlights. Thus E is the best answer.
While junk mail often comes from opt-in services, such as from businesses, spam refers to messages that the user did not opt to receive. When you're crafting a mailing list or sending out an advertisement, it's important that your message not come off as spam.
To learn more about spam and junk mail from given link
brainly.com/question/1285899
#SPJ4
Answer: <em>3w+4b</em>
Step-by-step explanation:
<em>Take your given equation</em>
<em>w+w+w+b+b+b+b</em>
<em>There are 3 w's and 4 b's</em>
<em>Combine like terms</em>
<em>w+w+w=</em><em>3w</em>
<em>b+b+b+b=</em><em>4b</em>
<em>3w+4b</em>
4x - y + 3 =0 is the equation of the line
Step-by-step explanation:
Given:
The slope of the line = 5
The points through with the line passes = (0,3)
To Find:
The equation of the line =?
Solution:
The equation y = mx + b
where m is the slope and (0,b) is the y-intercept.
The slope is given which is m = 4 and a point (0,3)
Then you can use slope-point equation

where
is the given point
y - (3) = 4(x - 0)
y - 3 = 4(x)
y = 4x - 22
y - 3 = 4x
4x - y + 3 = 0
<h3>
Answer: C) 142 degrees</h3>
=======================================================
Explanation:
Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.
We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.
For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A
A+N+T = 180
A+108+34 = 180
A+142 = 180
A = 180-142
A = 38
So angle NAT is 38 degrees.
----------------------------
Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.
We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees
----------------------------
The angles QSR and QST are a linear pair, so they are supplementary
(angle QSR) + (angle QST) = 180
angle QSR = 180 - (angle QST)
angle QSR = 180 - 38
angle QSR = 142 degrees