The speed of one type of bullet is 200 meters per second. How long would it take the bullet to travel 5,000 meters?

1 answer:

8 0

To solve this problem, we have to find how long it will take the bullet to travel 5,000 meters. We know that it travels 200 meters per second.

Therefore, if you divide 5,000 meters/200 meters per second, it will give you how many seconds it will take the bullet to travel 5,000 meters.

5,000/200 = 25

Therefore, it will take 25 seconds for the bullet to travel 5,000 meters.

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5x^2-2x=2<br>help plsmmm

Yuki888 [10]

Answer:

Presumably you're solving for x here? Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

$5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\$

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

$25x^2 - 10x - 10 = 0\\$

Now we'll add 11 to both sides:

$25x^2 - 10x + 1 = 11\\$

Which makes the left side a perfect square:

$(5x - 1)^2 = 11$

And now we can solve for x:

$(5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}$

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

$x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86$ $x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46$

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Mice21 [21]

Part 1: $\frac{5x^{3} + 10x^{2} + 15x}{5x} = \frac{5x^{3}}{5x} + \frac{10x^{2}}{5x} + \frac{15x}{5x} = x^{2} + 2x + 3$
The answer is C.

Part 2: $\frac{3x^{4} + 5x^{2} + 2x}{x} = \frac{3x^{4}}{x} + \frac{5x^{2}}{x} + \frac{2x}{x} = 3x^{3} + 5x + 2$
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hichkok12 [17]

Answer: $\dfrac{dT(t)}{dt}=77\times (450-T)$