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3 years ago

(x^2+5)^1/2+(x^2+5)^3/2

2 answers:

4 0

$\sqrt{ x^{2} +5} + \sqrt{ ( x^{2} +5)^{3} } = (\sqrt{ x^{2} +5})(1+ \sqrt{ ( x^{2} +5)^{2} } ) \\ =(\sqrt{ x^{2} +5})(1+ x^{2} +5 )=(\sqrt{ x^{2} +5})(x^{2}+6)$

Slav-nsk [51]3 years ago

3 0

(x²+5)½ + (x²+5)³/²

->(x+√5) +(x³+√125)
->(x+√5)+(x³+5√5)
->x+x³+√5+5√5
->2x³+6√5
->2(x³+3√5)

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A line passes through the point (-4,3) and has a slope of -5/2

Jlenok [28]

Answer:

y=(-5/2) x -7

Step-by-step explanation:

y=mx+b

m=(-5/2)

To find b:

3=(-5/2)times"x" + b

3=(-5/2)times(-4) + b

3= 10 +b; b=-7

y=(-5/2) x -7

7 0

3 years ago

How many solutions exist for the system of equations in the graph?

yan [13]

Answer:

Two

Step-by-step explanation:

Solutions are when the two graphs intersect

5 0

2 years ago

A sports club has 84 members who learned baseball, and 42 of those members also learned basketball. There are 25 students who di

HACTEHA [7]

<em>The table that shows the relative frequency of data is in the below further explanation.</em>

$\texttt{ }$

<h3>Further explanation</h3>

A set is a clearly defined collection of objects.

To declare a set can be done in various ways such as:

With words or the nature of membership

With set notation

By registering its members

With Venn diagrams

$\texttt{ }$

Multiplying set A x B is by pairing each member of set A with each member of set B.

<u>Example:</u>

Then

A x B = {(1, a), (1, b), (2, a), (2, b), (3, a), (3, b)}

$\texttt{ }$

Union of set A and B ( A ∪ B ) is rewriting each member A and combined with each member B.

Intersection of set A and B ( A ∩ B ) is to find the members that are both in Set A and Set B.

<u>Example:</u>

A ∪ B = {1, 2, 3, 4, 5}

A ∩ B = {3, 4}

Let us now tackle the problem!

$\texttt{ }$

<em>A sports club has 84 members who learned baseball, and 42 of those members also learned basketball.</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{42}& \\Don't Play Basketball& & \end{array}\right]$

$\texttt{ }$

Number of members who learned baseball but did not learn basketball will be ( 84 - 42 ) = 42 members

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42& \\Don't Play Basketball&\boxed{42}& \end{array}\right]$

$\texttt{ }$

<em>There are 25 students who did not learn baseball but learned basketball</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&\boxed{25} \\Don't Play Basketball&42& \end{array}\right]$

$\texttt{ }$

<em>8 students did not learn either baseball or basketball</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&25 \\Don't Play Basketball&42&\boxed{8} \end{array}\right]$

$\texttt{ }$

<em>Total Number of Students = 42 + 42 + 25 + 8 = 117</em>

$\texttt{ }$

Table of relative frequency

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{25}{117}} \\Don't Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{8}{117}} \end{array}\right]$