Answer:
The volume is 
Step-by-step explanation:
* Lets talk about the shell method
- The shell method is to finding the volume by decomposing
a solid of revolution into cylindrical shells
- Consider a region in the plane that is divided into thin vertical
rectangle
- If each vertical rectangle is revolved about the y-axis, we
obtain a cylindrical shell, with the top and bottom removed.
- The resulting volume of the cylindrical shell is the surface area
of the cylinder times the thickness of the cylinder
- The formula for the volume will be: 
where 2πx · f(x) is the surface area of the cylinder shell and dx is its
thickness
* Lets solve the problem
- To find the volume V generated by rotating the region bounded
by the curves y = 4e^x and y = 4e^-x about the y-axis by use
cylindrical shells
- Consider that the height of the cylinder is y = (4e^x - 4e^-x)
- Consider that the radius of the cylinder is x
- The limits are x = 0 and x = 1
- Lets take 2π and 4 as a common factor out the integration
∴ 
∴
- To integrate
and
we will use
integration by parts methods 
∵ u = x
∴ u' = du/dx = 1 ⇒ differentiation x with respect to x is 1
∵ v' = dv/dx = e^x
- The integration e^x is e^x ÷ differentiation of x (1)
∴
∴ 
- Similar we will integrate xe^-x
∵ u = x
∴ u' = du/dx = 1
∵ v' = dv/dx = e^-x
- The integration e^-x is e^x ÷ differentiation of -x (-1)
∴ 
∴ 
∴ V =
from 0 to 1
- Lets substitute x = 1 minus x = 0
∴ ![V=8\pi[(1)(e^{1})-(e^{1})+(1)(e^{-1})+(e^{-1})-(0)(e^{0})+(e^{0})-(0)(e^{0})-(e^{0})]](https://tex.z-dn.net/?f=V%3D8%5Cpi%5B%281%29%28e%5E%7B1%7D%29-%28e%5E%7B1%7D%29%2B%281%29%28e%5E%7B-1%7D%29%2B%28e%5E%7B-1%7D%29-%280%29%28e%5E%7B0%7D%29%2B%28e%5E%7B0%7D%29-%280%29%28e%5E%7B0%7D%29-%28e%5E%7B0%7D%29%5D)
∴ ![V=8\pi[e^{1}-e^{1}+e^{-1}+e^{-1}-0+1-0-1]=8\pi[2e^{-1}]=16\pi e^{-1}](https://tex.z-dn.net/?f=V%3D8%5Cpi%5Be%5E%7B1%7D-e%5E%7B1%7D%2Be%5E%7B-1%7D%2Be%5E%7B-1%7D-0%2B1-0-1%5D%3D8%5Cpi%5B2e%5E%7B-1%7D%5D%3D16%5Cpi%20e%5E%7B-1%7D)
∵ 
∴