given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.

Sample size n = 827

Sample proportion p = $\frac{438}{827} \\=0.5297$

$H_0: p =0.5\\H_a: p >0.5$

(right tailed test)

This is because they would be interested if more than half viewers are ready for the change

Test statistic = Z = p difference/std error

p difference = 0.0297

Std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174$

Z =1.708

p valu e= 0.9562

Since p >0.05 we fail to reject H0

Test statistic z= 1.708

8 0

3 years ago

Simplify (2x-1/x^2-2x-3) + (1/x-3) Please provide a step by step

topjm [15]

Answer:

(3x - 9)/(x² - 5x + 12)

Step-by-step explanation:

Answer attached, please refer it.

Hope it helps :)

8 0

3 years ago

Like has played 20 games and has a 95% winning percentage. Without losing anymore games how many games must he win in a row to g

stellarik [79]

Answer:

C) 4

Step-by-step explanation:

5 0

3 years ago