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Alisiya [41]
3 years ago
11

I need all the answers asp please

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

the answer is -360

Step-by-step explanation:

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PLS HELP AM I RIGHT!!!!? IF NOT PLEASE TELL ME AND SHOW YOUR WORK FOR 10 POINTS
Salsk061 [2.6K]

Answer:

you are correct

Step-by-step explanation:

since there is a box in the angle, it means it's 90°, so if the 1rst angle is 30°, the other one has to be 60°

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3 years ago
A student solved this problem and said the answer was 2 1 1/2 miles.
Cloud [144]
So do (21/2+49/4)-3/2=You get 21 1/4 miles
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4 0
4 years ago
5 times the sum of 7 and 23
scoundrel [369]
23 plus 7 is 30 and 30 plus 5 is 35
6 0
3 years ago
Read 2 more answers
In the figure find the value of x
NikAS [45]

Answer:

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1. Determine the discriminant and nature of roots of each quadratic equation.
Fiesta28 [93]

Answer:

Please check the explanation.

Step-by-step explanation:

The general quadratic equation is

ax²+bx+c=0

The discriminant = D = b² - 4ac

When b² - 4ac = 0 there is one real root.

When b² - 4ac > 0 there are two real roots.

When b² - 4ac < 0 there are two complex roots.

1) x² -6x + 9=0

On comparing with given quadratic equation x² -6x + 9=0

a = 1, b=-6, c=9

D = b² - 4ac

   = (-6)² - 4(1)(9)

   = 36 - 36

   = 0

D = 0

Thus, there is one real root of quadratic equation x² -6x + 9=0.

2) x² -4x + 3=0

On comparing with given quadratic equation x² -4x + 3=0

a = 1, b=-4, c=3

D = b² - 4ac

   = (-4)² - 4(1)(3)

   = 16 - 12

   = 4

D > 0

Thus, there are two real roots of quadratic equation x² -4x + 3=0.

3)  x² -7x - 4=0

On comparing with given quadratic equation x² -7x - 4=0

a = 1, b=-7, c=-4

D = b² - 4ac

   = (-7)² - 4(1)(-4)

   = 49 + 16

   = 65

D > 0

Thus, there are two real roots of quadratic equation x² -7x - 4=0

4)  2x² +3x +5=0

On comparing with given quadratic equation 2x² +3x +5=0

a = 2, b=3, c=5

D = b² - 4ac

   = (3)² - 4(2)(5)

   = 9 - 40

   = -31

D < 0

Thus, there are two complex roots of quadratic equation 2x² +3x +5=0

8 0
3 years ago
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