What is the sale price 45% of 69.50

We are given that a force of 40 N is exerted at an angle of 39°. Therefore, the force vector F can be represented as the hypoten

Deffense [45]

The answer is 0 degrees

6 0

3 years ago

Sam Sounds received a $290 discount loan to purchase a stereo. The loan was offered at 16% for 90 days. Find the interest in dol

garri49 [273]

I = Adt; where p = $290 is the Amount of the loan, d = 16% = 0.16 is the discount rate and t = 90days = 90/365 = 18/73 is the period.

I = 290 x 0.16 x 18/73 = 11.44
Interest = $11.44

Proceed = Amount - Interest = 290 - 11.44 = $278.56

6 0

3 years ago

Read 2 more answers

Choose the correct description of the graph of the compound inequality x − 2 > −4 and 3x less than or equal to 15.

Evgesh-ka [11]

Answer:

A number line with an open circle on −2, a closed circle on 5, and shading in between

Step-by-step explanation:

solve it you get x>-2

and 3x <=15

x<=5

so its close on 5 and open on -2

7 0

3 years ago

(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte

Hunter-Best [27]

(a) If

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then from the given conditions we get the system of equations,

f (-1) = a₀ - a₁ + a₂ - a₃ = -1

f (1) = a₀ + a₁ + a₂ + a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 8a₃ = 1

f (3) = a₀ + 3a₁ + 9a₂ + 27x ³ = 5

(b) Similarly, if

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then

f'(x) = a₁ + 2a₂ x + 3a₃ x ²

so that the given conditions yield the system,

f (1) = a₀ + a₁ + a₂ + a₃ = 0

f' (1) = a₁ + 2a₂ + 3a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 27a₃ = 3

f' (2) = a₁ + 4a₂ + 12a₃ = -1

7 0

2 years ago

If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

weeeeeb [17]

Answer:

Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$

7 0

3 years ago