What is an equation of the line that passes through the point (-4,-6)(−4,−6) and is perpendicular to the line 2x-y=62x−y=6?
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Answer:
Step-by-step explanation:
First create an equation in slope-intercept form, y = mx + b. To do this, find the rate of change or slope (m), and the y-intercept (b).
Using two pairs, (-7, -3) and (-8, -4),
m = 1
To find b, substitute m = 1, x = -7 and y = -3 into y = mx + b.
Thus:
-3 = (1)(-7) + b
-3 = -7 + b
-3 + 7 = b
4 = b
b = 4.
Replace y with f(x), m with 1 and b with 4 in y = mx + b.
The function would be: