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CaHeK987 [17]
3 years ago
15

Find the domain of the rational expression: x-4/2x-6

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

All real numbers except 3

Step-by-step explanation:

Given

\frac{x - 4}{2x - 6}

Required

Determine the domain

We start by writing the following inequality

2x - 6 \neq  0

Add 6 to both sides

2x -6 + 6 \neq = 0 + 6

2x \neq  6

Divide both sides by 2

\frac{2x}{2}\neq  \frac{6}{2}

x \neq  \frac{6}{2}

x \neq = 3

<em>As such, the domain of x is all real numbers except 3</em>

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Which do the following equations represent? -4x-5y=-4 and 10x-8y=-1
kicyunya [14]
Parallel have same slope
Perpendicular have opposite reciprocal slopes. Ex. 2/3 is slope of one line so the perpendicular line would have slope of -3/2.

Find slopes of these lines.

-4x-5y=-4
-4x+4 =5y
Divide by 5

Y= -4x/5 +4/5

Second line: 10x-8y=-1

10x+1=8y
Divide by 8

10x/8 +1/8 =y

Y= 5x/4 +1/8

So if you look at slope of line 1= -4/5 and line 2 it’s 5/4 so these both are perpendicular.
5 0
3 years ago
Solve for x. See attachment.....
N76 [4]
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64+4=4x
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8 0
3 years ago
Find the equation of the line with slope = 2 and passing through (-3 , 4)
coldgirl [10]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2. thus

y = 2x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - 6 + c ⇒ c = 4 + 6 = 10

y = 2x + 10 ← equation of line

8 0
3 years ago
Read 2 more answers
What is the expression is factored form? X^2 + 14x + 48
galben [10]

Answer:

Factored form of the expression is ( x+ 8)(x + 6).

Step-by-step explanation:

The given expression is x² + 14x + 48.

We have to convert the expression in factored form

x² + 14x + 48 = x² + 8x +6x + 48

= x(x + 8) + 6(x + 8) = (x + 8)(x + 6)

Therefore the factored form of the expression is (x + 8)(x + 6).

6 0
3 years ago
Read 2 more answers
Hi!
goblinko [34]
You can always add or subtract same value to/from both sides of equation. The same is true about multiplication and division.

In your case you have to subtract x from both sides of equation in order to get rid of it on the left side:
x+2y-x=8-x
2y=8-x

But it's easier to remember that if you want to move some member of equation to other side, you just have to change it's sign. Let's practice a bit using your equation (I have added "plus" signs where they are usually omitted to better understend what's going on):
+x+2y=+8

Move 2y to the right side:
+x=+8-2y

Move 8 to the left side:
+x+2y-8=0

Move both x and 2y to the right side:
0=8-x-2y
8 0
3 years ago
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