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Zina [86]
3 years ago
13

A rectangle had sides of 8.80 ft and 24.1 ft. Calculate the area of the rectangle in cm^2 (you should get 197000 cm^2) show your

work
Physics
1 answer:
Ratling [72]3 years ago
4 0

I ft  = 30.48 cm

length l = 8.80 ft = 8.80* (30.48 cm) = 268.224 cm

width w = 24.1 ft = 24.1 * (30.48 cm) = 734.568 cm

Area  A = l*w = (268.224 cm)(734.568 cm)

A = 197028 cm^2

A = 197000 cm^2

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three girls were pushing the same car with a net force of 450 N [N48°E]. Two of the girls were pushing with forces of 310 N [N25
ElenaW [278]

The net force is the vector

∑ F = (450 N) (cos(42°) i + sin(42°) j)

and two of the forces provided by the girls are

F₁ = (310 N) (cos(115°) i + sin(115°) j)

F₂ = (250 N) (cos(285°) i + sin(285°) j)

Then the force provided by the third girl is the vector

F₃ = ∑ F - F₁ - F₂

F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i

… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j

F₃ ≈ (400.722 N) i + (261.635 N) j

So, the third girl provided a force of magnitude

||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N

pointing in a direction

arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°

relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.

So, the third girl pushed with force 480 N [N57°E].

5 0
2 years ago
How does the heat enhance <br>the rate of chemical reaction ? Explain in short.​
densk [106]
When the reactants are heated, the average kinetic energy of the molecules increases. This means that more molecules are moving faster and hitting each other with more energy. If more molecules hit each other with enough energy to react, then the rate of the reaction increases.
3 0
3 years ago
What are beats and explain their formation.​
jekas [21]

Answer:

gdbenjjd kmnxjnhxhsbusndbuehie

Explanation:

shudhspywnhdbbdhojksc

6 0
3 years ago
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Because of inertia, it will be ____ to stop a larger object than a smaller object if they are both moving at the same speed.
strojnjashka [21]

Answer:

harder

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8 0
3 years ago
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A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on
postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R  (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

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Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0
3 years ago
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