1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anastaziya [24]
2 years ago
13

I need help with these. Please show workings​

Physics
2 answers:
Sauron [17]2 years ago
8 0

Answer:

Imp = 25 [kg*m/s]

v₂= 20 [m/s]

Explanation:

In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.

1)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})

where:

m₁ = mass of the object = 5 [kg]

v₁ = initial velocity = 0 (initially at rest)

F = force = 5 [N]

t = time = 5 [s]

v₂ = velocity after the momentum [m/s]

(5*0) +(5*5) = (m_{1}*v_{2}) = Imp\\Imp = 25 [kg*m/s]

2)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})\\(0.075*0)+(30*0.05)=(0.075*v_{2})\\v_{2}=20 [m/s]

solong [7]2 years ago
7 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Question 1)</h2><h2>_____________________________________</h2><h3>DATA:</h3>

Force = F = 5N

time = t = 5 seconds

mass = m = 5 kg

momentum = p = ?

<h2>_____________________________________</h2><h3>SOLUTION: </h3><h3>IMPULSE FORCE:</h3>

The force which acts for a very short period of time is called impulse force. It is given by,

                                      I = F x t

Where,

              I is impulse

              F is force

              t is time till which force is exerted

The impulse experienced by the object equals the change in momentum of the object. In equation form,

                                    F x t = M x ΔV

 So,

                     F x t = Final momentum - initial momentum

                     F x t = final momentum - (0)

initial momentum is zero because the object was initially at rest.

                     Final momentum = 5 x 5

                     Final momentum = 25 kgms^{-1}

So B is the answer

<h2>_____________________________________</h2><h2>Question 2) </h2><h2>_____________________________________</h2><h3>DATA: </h3>

Force = F = 30 N

time = t = 0.05 seconds

mass = m = 0.075 kg

V = ?

<h2>_____________________________________</h2><h3>SOLUTION:</h3>

impulse force is given by,

                                      I = F x t

Where,

              I is impulse

              F is force

              t is time till which force is exerted

The impulse experienced by the object equals the change in momentum of the object. So,

                                    F x t = M x ΔV

 So,

                     F x t = Final momentum - initial momentum

                     F x t = final momentum - (0)

Since it was at rest initially, initial momentum is zero.

Momentum is given by,

                                p = m x V

where,

           p is momentum

           m is mass

           v is velocity

<h3>So,</h3>

                 F x t = m x V

Rearrange the equation,

                                        V = \frac{Fxt}{m}

                                        V = \frac{(30)x(0.05)}{0.075} \\\\V = 20 m/s

So C is the answer

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>
You might be interested in
EMERGENCY! PLS HELP
Karolina [17]

Answer:

0.75 grams

Explanation:

Today we have 6 grams

In 30 years, 3 grams remain

In 60 years 1.5 grams remain

in 90 years 0.75 grams remain

mathematically It would look like this

m = 6(0.5⁽ⁿ/³⁰⁾) where n is number of years

5 0
2 years ago
A buoy is a floating device that can have many purposes, but often as a locator for ships. Collin constructs a hollow metal buoy
Yuri [45]

Answer:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water

B )angular frequency ( w ) = \sqrt{\frac{3g}{h} }

c )  h = 1.34 m ( 4\pi ^{2} / 3g )

Explanation:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water this is because the substances with lesser density floats when placed in a substance with a higher density

B ) when the Buoy is at rest ( t = 0 ) and is then pushed down calculate angular frequency ( w ) of small oscillations in terms of the given variables

volume of cone = hA /3.

h = height of cone, A = Base Area.

therefore the total volume of the Buoy above water level ( at rest )

= (\pi r^{2} * \frac{h}{3} ) * 2 = \frac{\pi r^{2} h  }{6}

The  part of the buoy immersed in water = x

then the net upward force will be

fb ( force of Buoy ) =  fg ( force of gravity )

note force = Mass * Acceleration

force of buoy = \frac{\alpha }{2} *\frac{\pi r^{2}  }{h}* a = ( force of gravity ) \alpha * T\frac{r^{2} }{4} * x * g

therefore a = \frac{3g}{h}  * x

angular frequency ( w ) = \sqrt{\frac{3g}{h} }

C ) height of the each cone

\frac{2\pi }{w}  = 1 therefore w = 2\pi

back to the angular frequency : \frac{3g}{h} = 4\pi ^{2}

therefore h = 1.34 m ( 4\pi ^{2} / 3g )

4 0
3 years ago
An object is held 24.8 cm from a lens of focal length 16.0 cm. What is the magnification of the image?
Gwar [14]

Answer: 1.8

Explanation:

You are given

the object distance U = 24.8 cm

Focal length F = 16.0 cm

First find the image distance by using the formula:

1/f = 1/u + 1/v

Where V = image distance

Substitute u and f into the formula

1/16 = 1/24.8 + 1/v

1/ v = 1/16 - 1/24.8

1/v = 0.0625 - 0.04032258

1/v = 0.022177

Reciprocate both sides by dividing both sides by one

V = 45.09 cm

Magnification M is the ratio of image distance to the object distance. That is,

M = V/U

Substitute V and U into the formula

M = 45.09/24.8

M = 1.818

Magnification of the image is therefore equal to 1.8 approximately

3 0
3 years ago
English or metric <br> What is 16in to cm
il63 [147K]
40.64 cm is the answer to your question.
6 0
3 years ago
Answer this question, please​
pashok25 [27]

Answer:

the correct answer is the 60

+ 20 + 60 \gamma  \beta

3 0
3 years ago
Other questions:
  • Ann is driving down a street at 64 km/h.
    5·2 answers
  • What is the standard unit used to measure mass?<br><br> cubic meters<br> gram<br> liter<br> meter
    7·2 answers
  • An egg is dropped from a building that is 61 m high.
    8·1 answer
  • Tectonic plates are large segments of the Earth's crust that move slowly. Suppose that one such plate has an average speed of 4.
    14·1 answer
  • Is a mirror transparent, translucent or opaque?
    8·2 answers
  • A bullet is fired from a rifle pointed 45 degrees above horizontal. The bullet leaves the muzzle traveling 1400 m/s. How many se
    7·1 answer
  • !!!!!PLEASE ANSWER CORRECTLY!! I DESPERATLY NEED HELP!!!!!
    6·1 answer
  • What would be the force required to accelerate an object that weighs 35 N up at a rate of .60 m/s^2?
    7·1 answer
  • Just as optical astronomers observe the visible light emitted by objects such as stars and galaxies, radio astronomers can also
    12·1 answer
  • What is the frequency of a radio wave of wavelength 150 m if the velocity of radio waves in free space is 3 × 10^8 m s–¹ ?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!