I need help with these. Please show workings
2 answers:
Answer:
Imp = 25 [kg*m/s]
v₂= 20 [m/s]
Explanation:
In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.
1)
where:
m₁ = mass of the object = 5 [kg]
v₁ = initial velocity = 0 (initially at rest)
F = force = 5 [N]
t = time = 5 [s]
v₂ = velocity after the momentum [m/s]
2)
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Question 1)</h2><h2>_____________________________________</h2><h3>DATA:</h3>
Force = F = 5N
time = t = 5 seconds
mass = m = 5 kg
momentum = p = ?
<h2>_____________________________________</h2><h3>SOLUTION: </h3><h3>IMPULSE FORCE:</h3>The force which acts for a very short period of time is called impulse force. It is given by,
I = F x t
Where,
I is impulse
F is force
t is time till which force is exerted
The impulse experienced by the object equals the change in momentum of the object. In equation form,
F x t = M x ΔV
So,
F x t = Final momentum - initial momentum
F x t = final momentum - (0)
initial momentum is zero because the object was initially at rest.
Final momentum = 5 x 5
Final momentum = 25
So B is the answer
<h2>_____________________________________</h2><h2>Question 2) </h2><h2>_____________________________________</h2><h3>DATA: </h3>Force = F = 30 N
time = t = 0.05 seconds
mass = m = 0.075 kg
V = ?
<h2>_____________________________________</h2><h3>SOLUTION:</h3>impulse force is given by,
I = F x t
Where,
I is impulse
F is force
t is time till which force is exerted
The impulse experienced by the object equals the change in momentum of the object. So,
F x t = M x ΔV
So,
F x t = Final momentum - initial momentum
F x t = final momentum - (0)
Since it was at rest initially, initial momentum is zero.
Momentum is given by,
p = m x V
where,
p is momentum
m is mass
v is velocity
<h3>So,</h3>F x t = m x V
Rearrange the equation,
V =
So C is the answer
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>You might be interested in
Answer:
<em>The total potential (magnitude only) is 11045.45 V</em>
Explanation:
<u>Electric Potential </u>
The total electric potential at location A is the sum of all four individual potentials produced by the charges, including the sign since the potential is a scalar magnitude that can be computed by
Where k is the Coulomb's constant, q is the charge, and r is the distance from the charge. Let's find the potential of the rightmost charge:
The potential of the leftmost charge is exactly the same as the above because the charges and distances are identical
The potential of the topmost charge is almost equal to the above computed, is only different in the sign:
The bottom charge has double distance and the same charge, thus the potential's magnitude is half the others':
The total electric potential in A is
The total potential (magnitude only) is 11045.45 V