Answer:
The requirements are missing, so I looked for similar questions. You should make any necessary adjusting entries on the accounting equation. Since there is not enough room here, I used an excel spreadsheet.
Answer:
Explanation:
1)
: All group means equal or 

At least one of the treatment group means are different
ANOVA TABLE
<u>Source of Variation SS df MS F P-value F crit
</u>
Between Groups 213.5 3 71.16667 0.65 0.5975 3.490295
Within Groups 1312.5 12 109.375
MSB = SSB / DFB = 71.16667
MSE = SSE / DFE = 109.375
F = MSB / MSE = 0.650667
3) P-value: 0.597576
The test statistic is not significant and failed to reject the null hypothesis.
4) The test statistic is not significant. So, there is no evidence to conclude that there is a difference between groups.
(12-6)/12 gives you the growth rate *over five years* (115%)
divide that by 5 and you get an average rate of 23% growth per year.
If we’re rounding, yes, that statement is correct. Otherwise, growth over five years doubled because there was a growth of 115% and year-over-year growth was 23%.
They should plant now rather than wait