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2 years ago

Find the y-intercept of the following equation. Simplify your answer. 10x + y = 8

Mathematics

1 answer:

vredina [299]2 years ago

4 0

Answer: 8

Explanation:

Form: y = mx + b

Where:
m is the slope
b is the y-intercept

We have:
10x + y = 8
y = -10x + 8

Thus, the y-intercept is 8

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avanturin [10]

From the list of 9 weights we see that

Puppies in range 10-11 = 3

range 12-13 = 4

range 14-15 = 2

The second histogram described is the correct one.

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3 years ago

For f(x)=3x+2 and g(x)=x^2-6, find (f o g)(4)

agasfer [191]

Answer:

Step-by-step explanation:

Evaluate g(4), then substitute the value obtained into f(x) , that is

g(4) = 4² - 6 = 16 - 6 = 10, then

f(10) = 3(10) + 2 = 30 + 2 = 32

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2 years ago

A company that manufactures cell phones has been given a quarterly operating budget of $1,176,912.42. The company's quarterly op

amm1812

Answer:

maximum is 16,853 cell phones

≤ 18.853

Step-by-step explanation:

1,176,912.42. per quarter budget

247,638.00 per quarter fixed cost

We subtract then divide the amount cost of phones and ensure its less or rounded down.

1,176,912.42 -247,638 = 929274.42

929274.42 / 55.14 = 16853

16,852 < m ≤ 16,853

6 0

2 years ago

arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)

cupoosta [38]

We have to rationalize the denominator:
$\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\ \frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{ \sqrt{x+y-2}+ \sqrt{x+y+2} }= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-(x+y+2)}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-x-y-2}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2} }{-4}= \\ \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{2}$

6 0

2 years ago

Read 2 more answers

The shown bellow question answer

Serhud [2]

Answer:

The area of the shape can be divided into the area of the rectangle, and the area of the semi-circle.

The area of the rectangle can be found by $11*4=44$

The area of a semi-circle can be found with the formula $\frac{1}{2} \pi r^2$ where r is the radius.

Since we know the diameter of the semi-circle is 4,

the radius will be 4 ÷ 2 = 2.

Therefore, the area of the semi-circle is $\frac{1}{2}\pi 2^2=\frac{1}{2}\pi*4=2\pi$

Therefore, the area of the shape is $44+2\pi$ or $50.283cm^2$ (3 decimal places)

3 0

2 years ago