Why is an objects speed affected by the volume of space it is confined in

A student plucks a fixed-end string, creating a standing wave with 6.00 nodes (including any nodes at the ends). The string is t

Vesna [10]

1) 2.5 wavelengths

2) 0.208 m

3) 1731 Hz

Explanation:

1)

Standing waves are waves that do not propagate, but instead the particles of the medium just oscillate around a fixed position. Examples of standing waves are the waves produced on a string with fixed ends.

The points of a standing wave in which the amplitude of the oscillation is always zero are called nodes.

The two fixed ends of the string are two nodes. In this problem, we have a total of 6 nodes along the string: this means that there are 4 additional nodes apart from the two ends of the string.

Therefore, this also means that the string oscillate in 5 different segments.

One wavelength is equal to 2 segments of the oscillation: therefore, since here there are 5 segments, this means that the number of wavelengths that we have in this string is

$n=\frac{5}{2}=2.5$

2)

The wavelength of a wave is the distance between two consecutive crests (or throughs) of the wave.

The wavelength of a standing wave can be also measured as the distance between the nth-node and the (n+2)-th node: so, basically, the wavelength in a standing wave is twice the distance between two nodes:

$\lambda = 2 d$

where

$\lambda$ is the wavelength

d is the distance between two nodes

Here the length of the string is

L = 0.520 m

And since it oscillates in 5 segments, the distance between two nodes is

$d=\frac{L}{5}=\frac{0.520}{5}=0.104 m$

And therefore, the wavelength is

$\lambda=2d=2(0.104)=0.208 m$

3)

The frequency of a wave is the number of complete oscillations of the wave per second.

The frequency of a wave is related to its speed and wavelength by the wave equation:

$v=f\lambda$

where

v is the speed

f is the frequency

$\lambda$ is the wavelength

In this problem:

v = 360 m/s is the speed of the wave

$\lambda=0.208 m$ is the wavelength

Therefore, the frequency is

$f=\frac{v}{\lambda}=\frac{360}{0.208}=1731 Hz$

3 0

3 years ago

Compare and contrast the temperatures of the inner planets?

Zarrin [17]

Answer:

The inner planets either do not have moons or have just one (Earth) or two (Mars). None of the inner planets have rings. Compared to the outer planets, the inner planets have shorter orbits around the Sun, but all the inner planets spin more slowly. ... From left to right, they are Mercury, Venus, Earth, and Mars.

Explanation:

8 0

3 years ago

What is the wavelength of a light ray that has a frequency of 7.4 E12 Hz?

const2013 [10]

The wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.

Given the data in the question;

Frequency of the light ray; $f = 7.4 * 10^{12}Hz$

Wavelength; $\lambda = \ ?$

<h3>Wavelength</h3>

Wavelength can be simply defined as the spatial period of a periodic wave. When the shapes of waves are repeated, the distance over which they are repeated is called wavelength. Wavelength is expressed as;

$\lambda = \frac{c}{f}$

Where $\lambda$ is wavelength, f is frequency and c is speed of light( $c = 3*10^8m/s$ )

We substitute our values into the expression above to determine the wavelength of the light ray.

$\lambda = \frac{c}{f} \\\\\lambda = \frac{3*10^8m/s}{7.4*10^{12}s^{-1}}} \\\\\lambda = \frac{3*10^8ms/s}{7.4*10^{12}}}\\\\\lambda = 4.05*10^{-5}m\\\\\lambda = 4.05*10^{4}nm$

Therefore, the wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.

Learn more about wavelength: brainly.com/question/16776907

5 0

2 years ago

State Newton's laws of motion

madam [21]

Answer:

Newtons First Law (The Law of Inertia)- If an object is at rest it will stay at rest until a net force acts on it. If an object is in motion it will stay in motion until a net force acts on it.

Newtons Second Law (F=ma)- Force equals the mass of an object times it's acceleration.

Newton's Third Law- For every action there is an equal and opposite reaction.

hope this helps!

4 0

3 years ago

Read 2 more answers

A proton, moving in a uniform magnetic field, moves in a circle perpendicular to the field lines and takes time T for each circl

xxMikexx [17]

Answer:

option (B)

Explanation:

mass of proton, m = m