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SVEN [57.7K]
4 years ago
12

A uniform solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 33.4

rpm. What is its kinetic energy?
Physics
1 answer:
DENIUS [597]4 years ago
5 0

Answer:

Is the equation for Ec=1/2 m(Dv)^2 where Dv is the difference between the angular speed & the areolar speed?

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C Determine the coulomb's force between the electron and the nucleus in
tiny-mole [99]

Answer:

F = 2.3 x 10⁻⁸  N

Explanation:

Given,

The mean distance between the electron and the nucleus, x = 1 x 10⁻¹⁰ m

The number of protons present in the nucleus of the hydrogen atom is 1.

The charge of the proton and electron,  q = 1.602 x 10⁻¹⁹ C

Since they have opposite charges, the force between them is attractive,

The coulomb law of force between two charges is given by the formula,

                          <em> F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}</em>

                           \frac{1}{4\pi\epsilon_{0}}   = 9 x 10⁹ Nm²C⁻²

Substituting the values in the above equation

                              F = 9 x 10⁹ X (1.602 x 10⁻¹⁹)² / (1 x 10⁻¹⁰)²

                                 = 2.31 x 10⁻⁸  N

Hence, the force between the nucleus and electron of hydrogen atom is, F = 2.3 x 10⁻⁸  N

6 0
3 years ago
A piece of metal and a piece of brick are both sitting in the sun if both are the same mass what property of matter will make th
xenn [34]
The piece of metal will feel hotter to touch because of its heat conductance. whereas the brick does not conduct heat as well as the metal. Hence the piece of metal feeling hotter to touch. 
5 0
3 years ago
Consider two uniform solid spheres where one has twice the mass and twice the diameter of the other. The ratio of the larger mom
Firdavs [7]

Answer:

The ratio of moment of inertia of larger sphere to that of smaller sphere = 4

Explanation:

The moment of inertia of solid sphere is given by I = 2/5MR² where M = mass of sphere and R = radius of sphere.

Radius of smaller sphere = D/2

Radius of larger sphere = 2D/2 = D.

Moment of inertia of smaller sphere I₁ = 2/5M × D²/4 = MD²/10

Moment of inertia of larger sphere I₂ = 2/5M × D² = 2MD²/5

The ratio of moment of inertia of larger sphere to that of smaller sphere = I₂/I₁ = 2MD²/5 ÷ MD²/10 = 10 × 2/5 = 4

7 0
3 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the
Over [174]

Answer:

Part a)

a= 0.32 m/s^2

Part b)

F_c = 3.6 N

Part c)

F_c = 5.5 N

Explanation:

Part a)

As we know that the friction force on two boxes is given as

F_f = \mu m_a g + \mu m_b g

F_f = 0.02(10.6 + 7)9.81

F_f = 3.45 N

Now we know by Newton's II law

F_{net} = ma

so we have

F_p - F_f = (m_a + m_b) a

9.1 - 3.45 = (10.6 + 7) a

a = \frac{5.65}{17.6}

a= 0.32 m/s^2

Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

F_c - F_f = m_b a

F_c = \mu m_b g + m_b a

F_c = 0.02(7)(9.8) + 7(0.32)

F_c = 3.6 N

Part c)

If Alex push from other side then also the acceleration will be same

So for box B we can say that Net force is given as

F_p - F_f - F_c = m_b a

9.1 - 0.02(7)(9.8) - F_c = 7(0.32)

F_c = 9.1 - 0.02 (7)(9.8) - 7(0.32)

F_c = 5.5 N

3 0
3 years ago
A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required
Ad libitum [116K]

Answer:

4N

Explanation:

a = (7-3)/5 = 0.8m/s^2

F = ma = (5)(0.8) = 4 Newtons

3 0
3 years ago
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