We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:

which means

The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (

):

Therefore, the kinetic energy gained by the proton is

<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
Answer:
The magnitude of induced emf is 5.4 V
Explanation:
Given:
Magnetic field
T
Area of loop

Time take to reduce loop to zero
sec
To find induced emf we use faraday's law,
Induced emf is given by,

Here minus sign shows lenz law, for finding magnitude of emf we ignore it.
Where
Put the value of flux and find induced emf,


V
Therefore, the magnitude of induced emf is 5.4 V
There are 8 hydrogen atoms
A satellite is a moon, planet or machine that orbits a planet or star.
4.3A.
The easiest way to solve this problem is find the equivalent resistance for parallel resistor 1/Req = 1/R1 + 1/R2 + 1/R3 in the three-branch parallel network with branches whose resistance are 8Ω.
1/Req = 1/8 Ω + 1/8 Ω + 1/8 Ω
1/Req = 3/8 Ω
Req = 8/3 Ω = 2.667Ω
Req = 2.7Ω
So, the equivalent circuit will be the 20.0V battery in series with a resistor 2.0Ω and the equivalent resistor 2.7Ω.
Using Ohm's Law to find the current provide by the 20.0V voltage source:
V = I*R ------> I = V/R
I = 20.0V/(2.0Ω + 2.7Ω)
I = 20.0V/4.7Ω
I = 4.3A