Answer:
221.17 kJ
Explanation: Note the heat of vaporization is in kJ/mol,then to determine the number of moles of water: divide the mass by 18. Then multiply the number of moles by the molar heat of vaporization of water.
N = 97.6 ÷ 18
Q=molar heat *moles
Q = (40.79) * (97.6 ÷ 18)
This is approximately 221.17 kJ
Answer:
- 0.09 % of the original radioactive nucllde its left after 10 half-lives
- It will take 241,100 years for 10 half-lives of plutonium-239 to pass.
Explanation:
The equation for radioactive decay its:
,
where N(t) its quantity of material at time t,
its the initial quantity of material and
its the mean lifetime of the radioactive element.
The half-life
its the time at which the quantity of material its the half of the initial value, so, we can find:

so:




So, after 10 half-lives, we got:




So, we got that a 0.09 % of the original radioactive nucllde its left.
Putonioum-239 has a half-life of 24,110 years. So, 10 half-life will take to pass

It will take 241,100 years for 10 half-lives of plutonium-239 to pass.
Answer:
increase speed, decrease speed, and change direction
Explanation:
The correct answer is:
Consideration
<em>Consideration</em> is defined as the act of thinking something carefully, careful thought; meditation; deliberation. Consideration acts like filter on the information a person receives, because it allows them to contemplate the implications of something before acting on it.
Answer:
#_photon = 7 10²¹ photons
Explanation:
Let's look for the power that affects the panel of area of 1.5 m2
I = P / A
P = I A
P = 1.37 10³ 1.5
P = 2,055 10³ W
P = E / t
If we use t = 1 s
E = P t
E = 2,055 10³ J
This is the power that the panel receives, let's look for the energy of a photon
E = h f
c = λ f
f = c /λ
E = h c /λ
Let's calculate
E₀ = 6.63 10⁻³⁴ 3 10⁸/680 10⁻⁹
E₀ = 2.925 10⁻¹⁹ J
In one second the total energy is the number of photons for the energy of each one
E = #_photon E₀
#_photon = E / E₀
#_photon = 2,055 10³ / 2,925 10⁻¹⁹
#_photon = 7 10²¹ photons