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Zolol [24]
4 years ago
7

The dashboard in your car shows an outside temperature of 73°F. A minute later it reads 72°F. This is an example of _____.

Physics
1 answer:
Furkat [3]4 years ago
4 0
Analog information is the correct answer.
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The spectra of most galaxies show redshifts. this means that their spectral lines _________.
spin [16.1K]
Have wavelengths that are longer than normal.
3 0
3 years ago
An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the
poizon [28]

Answer:

Inverted

Real

Explanation:

u = Object distance =  30 cm

v = Image distance

f = Focal length = 10 cm

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{10}-\frac{1}{30}\\\Rightarrow \frac{1}{v}=\frac{1}{15}\\\Rightarrow v=15\ cm

As, the image distance is positive the image is real and forms on the other side of the lens

m=-\frac{v}{u}\\\Rightarrow m=-\frac{-15}{30}\\\Rightarrow m=-0.5

As, the magnification is negative the image is inverted

3 0
3 years ago
Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ
Oksi-84 [34.3K]

Answer:

The number is  Z = 216 \ fringes

Explanation:

From the question we are told that

      The wavelength is  \lambda  =  520 \ nm =  520 *10^{-9} \ m

       The length of the glass plates is y  = 21.1cm = 0.211 \ m

      The distance between the plates (radius of wire ) =  d =  0.028 mm  =  2.8 *10^{-5} \  m

   Generally the condition for constructive  interference in a film is mathematically represented as

            2 *  t  = [m +  \frac{1}{2}  ]\lambda

Where  t is the thickness of the separation between the glass i.e  

    t  = 0 at the edge where the glasses are touching each other and  

     t =  2d at the edge where the glasses are separated by the wire  

   m is the order of the fringe it starts from  0, 1 , 2 ...

So  

       2 *  2 * d   = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>   2 *  2 *   (2.8 *10^{-5}) = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>    

       m = 215

given that we start counting m from zero

   it means that the number of  bright fringes that would appear is

         Z =  m + 1

=>    Z =  215 +1

=>     Z = 216 \ fringes

3 0
3 years ago
What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, start
Llana [10]

Answer:

v_f=41.65\frac{m}{s}

Explanation:

The final velocity is given by the following kinematic equation:

v_f=v_0+at

Here, v_0 is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

7.5min*\frac{60s}{1min}=450s

Now, we calculate the final velocity:

v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}

4 0
3 years ago
Light is incident perpendicularly on four transparent films of different thickness. The thickness of each film is given in the d
exis [7]

Answer:

1/4 λ film

Explanation:

Let L = total path length then L = 2 t where t is film thickness

There will be a 180 deg phase change at the air-film interface but no

phase change at the film-air interface

L = n * wavelength / 2 where n = 1, 3, 5, 7 etc

(the total path L must be an odd number of 1/2 wavelengths)

Or t = n * wavelength / 4 (the film must be an odd number

of 1/4 wavelengths thick)

1/4 λ film satisfies this condition

Note: Find the missing diagram in the attachment section.

6 0
3 years ago
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