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Degger [83]
3 years ago
7

What is the formula for the speed of a car

Physics
2 answers:
Likurg_2 [28]3 years ago
3 0
The formula for speed is s = d/t, where s is speed, d is distance, and t is time. The formula can be applied to all objects, including cars, to find their speed.
Bingel [31]3 years ago
3 0

Answer:

\huge \boxed{S =\frac{d }{t} }

\rule[225]{225}{2}

Step-by-step explanation:

The formula to find speed is as follows:

\Longrightarrow \ \  \displaystyle \sf speed =\frac{distance \ travelled }{time \ taken}

\Longrightarrow \ \  \displaystyle S =\frac{d }{t}

We can find the speed of a car with this formula.

\rule[225]{225}{2}

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How is force defined?​
ArbitrLikvidat [17]

Answer:

In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull.

7 0
3 years ago
Approximately how far, in cm, does the blood move during one beat?
laiz [17]
10cm per beat, it would take 3 beats to travel 30cm x
6 0
3 years ago
Consider two massless springs connected in series. Spring 1 has a spring constant k1, and spring 2 has a spring constant k2. A c
Andru [333]

Answer:

a. k = (1/k₁ + 1/k₂)⁻¹ b. k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

Explanation:

Since only one force F acts, the force on spring with spring constant k₁ is F = k₁x₁ where x₁ is its extension

the force on spring with spring constant k₂ is F = k₂x₂ where x₁ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂

x = F/k = F/k₁ + F/k₂

1/k = 1/k₁ + 1/k₂

k = (1/k₁ + 1/k₂)⁻¹

B

The force on spring with spring constant k₃ is F = k₃x₃ where x₃ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂ + x₃

x = F/k = F/k₁ + F/k₂ + F/k₃

1/k = 1/k₁ + 1/k₂ + 1/k₃

k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

8 0
3 years ago
Read 2 more answers
If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f
Free_Kalibri [48]

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

k = 500N/m --- spring constant

x = 0.5m --- stretch

Required

The amount of energy

This is calculated as:

U = \frac{1}{2} kx^2

U = \frac{1}{2} * 500N/m * (0.5m)^2

U = 250N/m * (0.5m)^2

U = 62.5\ J

7 0
3 years ago
A 77.0 kg firefighter climbs a flight of stairs 8.0 m high. how much work is required? 0 incorrect: your answer is incorrect. j
Alex73 [517]
<span>6160 joules

    to lift 1 newton 1 metre requires 1 joule
 there are 10 newtons in one kilo

    so 77(kg) x 8 (metres) x 10 (newtons/kilo) = 6160 joules</span>
5 0
3 years ago
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