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Oksana_A [137]
3 years ago
7

For an object in damped harmonic motion with initial amplitude a, period 2π/ω, and damping constant c, find an equation that mod

els the displacement y at time t for the following.
(a)
y = 0 at time t = 0
y= ?
(b)
y = a at time t = 0
y= ?
Mathematics
1 answer:
Kay [80]3 years ago
3 0

Answer:

  see below

Step-by-step explanation:

We presume the damping constant is the opposite of the multiplier of time in the exponential term. Then the equations are ...

(a)  y = a·e^(-ct)·sin(ωt)

(b)  y = a·e^(-ct)·cos(ωt)

__

These are the standard equations for simple harmonic motion assuming there is no driving function.

  a = initial amplitude*

  c = damping constant**

  ω = frequency of oscillation in radians per second

  t = time in seconds

_____

* Of course, when y(0) = 0, the motion never actually reaches this amplitude because it is subject to decay before it can.

__

** In electrical engineering, damping is often specified in terms of a time constant, the time it takes for amplitude to decay to 1/e (≈36.8%) of the original amplitude. If that time is represented by τ, then the exponential factor is e^(-t/τ).

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The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check
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Answer:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =150 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

\bar X = \frac{740+920}{2} = 830

and the margin of error is given by :

ME = \frac{920-740}{2}= 90

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (b)

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n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

5 0
3 years ago
find the area of the shape below
Norma-Jean [14]

Answer:

235 cm²

Step-by-step explanation:

Find area of the large rectangle on the bottom. To do that, find its length and width, then multiply them together.

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Width of big rectangle=9 cm

20x9=180 cm²

Next, find the area of the small rectangle on the top. To do that, find its length and width, then multiply them together.

Length of small rectangle=11 cm

Width of small rectangle=5 cm

I found the width by subtracting 9 from 14, since the 9 cm is part of the large rectangle.

11x5=55 cm²

Add the areas of the two rectangles.

55+180=235 cm²

5 0
3 years ago
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