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gulaghasi [49]
3 years ago
7

C. Graphite is used as lubricant.​

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

is this the question?please

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Balance the equations below by adding coefficients. Enter a number in each blank, entering "1" when necessary.
neonofarm [45]

Answer:

1. CO₂ → C + O₂

2. Fe₂ + O₂ → 2FeO

3. 2Al + 3CuO→  Al₂O₃  +  3Cu

Explanation:

1. 1 mol of CO₂ decomposes to 1 mol of C and 1 mol of oxygem

2. 1 mol of Fe₂ reacts with 1 mol of oxygen to produce 2 moles of iron (II) oxide

3. 2 moles of Al, reacts with 3 moles of cupper(II) oxide to produce 1 mol of aluminum dioxide and 3 moles of cupper

3 0
3 years ago
Read 2 more answers
Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points
Free_Kalibri [48]

523.15

brainliest please

I answerd

6 0
3 years ago
The pH of a vinegar solution is 4.15. What is the H3O+ concentration of the solution?
riadik2000 [5.3K]
PH = -log [H3O+]
4.15 = -log [H3O+]
[H3O+] = 10^(-4.15)
[H3O+]= 7.08 × 10^-5
8 0
3 years ago
Read 2 more answers
the following reaction gives a product with the molecular formula c4h8o2. draw the structure of the product.
grandymaker [24]

The following reaction gives a product with the molecular formula C₄H₈O₂. The diagram of the structure of the product can be seen in the image attached below.

The reaction between C₂H₂(ONa)₂ and C₂H₄Br results in the formation of the product C₄H₈O₂ and 2NaBr.

This reaction undergoes an SN₂ mechanism since there is no stable carbocation formed. In the reaction -O⁻Na⁺ attacks the ortho position in C₂H₄Br to form C₄H₈O₂.

In  SN₂ mechanism is a nucleophilic substitution reaction where one bond is formed while another one is broken simultaneously.

The mechanism for the reaction can be seen in the image attached below.

Learn more about nucleophilic substitution reaction here:

brainly.com/question/4699407?referrer=searchResults

7 0
3 years ago
What is the number of moles of 27.6 grams of lithium
Leya [2.2K]
Lithium's atomic weight is 6.94 g/mol.

27.6 g Li (\frac{mol}{6.94 g}) = 3.98 mol Li

Need anything else?

6 0
3 years ago
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