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ipn [44]
3 years ago
5

Is potential or kinetic energy affected by mass?

Chemistry
2 answers:
Levart [38]3 years ago
7 0

Answer:

I think the Answer is Yes

Shkiper50 [21]3 years ago
3 0

Answer: Yes, Because kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on translational kinetic energy. Doubling the mass of an object will only double its kinetic energy, but doubling the velocity of the object will quadruple its velocity.

Common types of potential energy include the gravitational potential energy of an object that depends on its mass and its distance from the center of mass of another object, the elastic potential energy of an extended spring, and the electric potential energy of an electric charge in an electric field.

Explanation: happy help

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No matter where you are on Earth, the center of the Earth is always _______.
FinnZ [79.3K]

Answer:

D) straight down

Hope this helps!

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3 years ago
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Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chloroc
Allushta [10]

Answer:

Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chlorocycloheptanol (d) 1,4-Pentanediol(e) 2,6-Dimethylphenol (f ) o-(2-Hydroxyethyl)phenol

Explanation:

According to IUPAC rules, the name of a compound is:

Prefix+root word+suffix

1) Select the longest carbon chain and it gives the root word.

2) The substituents give the prefix.

3) The functional group gives the secondary suffix and the type of carbon chain gives the primary suffix.

The structure of the given compounds are shown below:

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3 years ago
A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif
slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})

where,

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m_1 = Mass of metal= 19 g

T_1 = Initial  temperature of metal = 35^oC

T_2 =Final  temperature of metal = 175^oC

c = specific heat of metal= ?

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c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}

c=0.0702J/g^oC

0.0702J/g°C the specific heat capacity of the metal.

6 0
3 years ago
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