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scoundrel [369]
3 years ago
10

If a simple machine aduces the strength of a force, what must be increased?

Chemistry
1 answer:
Svetach [21]3 years ago
5 0

Answer:

the work the simple machine performs (second choice)

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Consider the reaction
Fofino [41]
a) According to the reaction equation:

CaSO4(s) ↔ Ca2+(aq)  + SO4-(aq)

when Kc = [Ca2+][SO4-]

when [Ca2+] = [SO4-] = X

and we have Kc = 2.4 x 10^-5 so ,by substitution we can get [Ca2+]&[SO4-] 

2.4 x 10^-5 = X^2

∴X = 0.0049

∴[SO4-] = [Ca2+] = 0.0049 M

b) when we have [Ca2+] =  0.0049 M so we can get the no.of moles of CaSO4:

moles of CaSO4 = molarity * volume 

                             = 0.0049 M * 1.2 L
                             = 0.00588 moles

when we know the molar mass of CaSO4 = 136.14 g/ mol, So we can get the mass:

∴mass of CaSO4 = moles of CaSO4 * molar mass of CaSO4

                             = 0.00588 moles * 136.14 g/mol

                             = 0.8 g
8 0
3 years ago
Read 2 more answers
Which of the following destroys the marine ecosystem?
nalin [4]
C. Dynamite fishing

dynamite fishing is a destructive fishing practice using explosives to stun or kill schools of fish for easy collection. This often illegal practice is extremely destructive to the surrounding ecosystem, as the explosion often destroys the underlying habitat that supports the fish.
7 0
3 years ago
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WILL PICK BRANLIEST!! EACH ONE IS ONE OF THE FOUR CHOICES ON THE BOTTOM
Minchanka [31]

Hello there!

{{\boxed{anaphaseI}}: Homologous chromosomes are separated.

\boxed{prophaseI}: Nuclear envelopes form around separated chromosomes.

\boxed{Telophase}: Homologous chromosome are paired.

\boxed{metaphasel}: The centrosome replicates.

I hope this helps you!


7 0
3 years ago
The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)
Yuki888 [10]
Carbon dioxide and water are the products
8 0
3 years ago
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Calculate the cell potential at 25oC under the following nonstandard conditions: 2MnO4-(aq) + 3Cu(s) + 8H+(aq) ⟶ 2MnO2(s) + 3Cu2
baherus [9]

Answer:

1.346 v

Explanation:

1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:

(oxidation) Cu_{(s)} →Cu^{2+}_{(aq)} +2e E°=0.337 v

(reduction) MnO_{4 (aq)} + 3e + 4H^{+}_{(aq)}→MnO_{2 (aq)}+2H_{2}O E°=1.679 v

(overall) 2MnO_{4 (aq)}+3Cu_{(s)}+8H^{+}_{(aq)}→3Cu^{2+}_{(aq)}+2MnO_{2 (aq)}+4H_{2}O E°=1.342 v

2) Nernst Equation

Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

5 0
3 years ago
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