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2 years ago

If a simple machine aduces the strength of a force, what must be increased?

Chemistry

1 answer:

Svetach [21]2 years ago

5 0

Answer:

the work the simple machine performs (second choice)

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Explain the terms physical properties of metals Malleability and ductility, and how they used in daily life situation ?

EastWind [94]

Answer:

Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.

and For jewellery and ornaments, gold, platinum and silver are being used. For building purposes, iron and steel can be used. Iron and aluminium are used as utensils. The thermometer uses mercury and helps to monitor the temperature.

Explanation:

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11 months ago

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What do scientists suspect the core might be made of?

nikklg [1K]

If your question is of the core of the Earth, it is suspected to be made of iron and nickel.

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3 years ago

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Hope this helps with my last question or I wasted my points

Talja [164]

Anyone else just hate chemistry

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2 years ago

A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em

Neporo4naja [7]

Answer: The empirical formula is $H_2S_2O_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles$

Mass of S = $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = $\frac{1.8}{1.8}=1$

For S = $\frac{1.8}{1.8}=1$

For O = $\frac{2.6}{1.8}=1.5$

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is $H_2S_2O_3$

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2 years ago

What happens when a hydrocarbon combusts?

8_murik_8 [283]

Answer:

Hydrocarbon combustion refers to the chemical reaction where a hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat. Hydrocarbons are molecules consisting of both hydrogen and carbon. ... Methane combining with 2 oxygen to form carbon dioxide, water and heat.

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2 years ago