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Phoenix [80]
3 years ago
12

Which substances will make a salt when combined?

Chemistry
2 answers:
MariettaO [177]3 years ago
7 0

Answer:

Sodium and chlorine combine to make salt

Explanation:

Crazy boy [7]3 years ago
5 0

Answer:

vinegar and soda

Explanation:

:)

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3 years ago
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After observing (you can repeat the process more than once), write a general statement explaining how reducing the volume change
ad-work [718]

Answer:

The correct answer is that both molecular motion, pressure and temperature increase as volume reduces.

Explanation:

A reduction in volume changes the molecular motion, temperature and pressure of the system. When the volume of the container decreases, this causes the pressure to increase, the temperature to increase and the molecular motion to increase. This is because a liquid and a solid are incompressible, so by reducing the volume of a gas, the molecules increase their movement as the temperature of the system increases, which is due to the increased pressure applied to reduce the volume of the system.

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4 0
3 years ago
How the Atmosphere affects the Biosphere pls help
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Explanation:

Air pollutants also affect the biosphere in turn. Ozone and acid deposition suppress plant growth; meanwhile, aerosols and their indirect effects on clouds decrease total photosynthetically active radiation (PAR) while increasing the diffuse fraction.

6 0
3 years ago
How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?
slavikrds [6]

Answer:

V_{LiOH}=21.8mL

Explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

n_{LiOH}=n_{HBr}

That it terms of molarities and volumes we have:

M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}

Next, solving for the volume of lithium hydroxide we obtain:

V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL

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8 0
3 years ago
A container initially holds 5.67 x 10^-2 mol of propane and has a volume of V1. The volume of the container was increased by add
Brut [27]

Answer:

Initial volume of the container (V1) = 1.27 L (Approx)

Explanation:

Given:

Number of mol (n1) = 5.67 x 10⁻²

Number of mol (n2) = (5.67 +2.95) x 10⁻² = 8.62 x 10⁻²

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Find:

Initial volume of the container (V1)

Computation:

Using Avogadro's law

V1 / n1 = V2 / n2

V1 / 5.67 x 10⁻² = 1.93 / 8.62 x 10⁻²

V1 = 10.9431 / 8.62

Initial volume of the container (V1) = 1.2695

Initial volume of the container (V1) = 1.27 L (Approx)

5 0
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