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pychu [463]
2 years ago
12

A normal deck of 52 cards includes 4 suits where each suit ranges from 2 though 10 inclusive, Jack, Queen, King and Ace. In a st

andard deck of 52 cards laying face down, if you select one card from the pile, what is the probability you select a diamond and a face card (jack, queen or king)?
Mathematics
1 answer:
vlabodo [156]2 years ago
6 0

Answer: 3/52 (~5.77%)

<h3>Explanation:</h3>

What we know:

  • There is a deck of 52 total cards
  • These are split into 4 suits
  • Each suit contains cards of 2-10, and a Jack, Queen, King, and Ace

How to solve:

  We need to find the probability of drawing one of 3 diamond face cards, which gives us all of the information we need. Using division, we can create a 'x amount of diamond face cards/y amount of total cards' probability.

<h3>Process:</h3>

Probability of a diamond  face card

<em>Where P is the probability of drawing that card, x is the number of diamond face cards, and y is the total amount of cards.</em>

Set up equation                                                     P = x/y

Substitute                                                               P = (3)/(52)

Answer: 3/52 (~5.77%)

Because there are 3 diamond face cards in the deck, the chance of drawing one is {3 cards out of 52 total}, which is 3/52.

The chance of drawing ANY face card is {(3 per suit, 4 suits=) 12 cards out of 52 total} 12/52 (~23.08%),

The chance of drawing ANY diamond card is {1 suit out of 4 suits} 1/4 (25%)

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Answer:

1/10 as a percent is 10%

1/5 as a percent is 20%

Step-by-step explanation:

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Answer:

Kristi

Step-by-step explanation:

The formula for Simple Interest =

Principal × Rate × Time

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Principal = $3000

Rate = 7.25% = 0.0725

Time = 1

Simple interest = $3000 × 0.0725 × 1

= $217.5

For Kari

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Principal = $3200

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Time = 1

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Match the features of the graph of the rational function.
Sunny_sXe [5.5K]

After applying <em>algebraic</em> analysis we find the <em>right</em> choices for each case, all of which cannot be presented herein due to <em>length</em> restrictions. Please read explanation below.

<h3>How to analyze rational functions</h3>

In this problem we have a rational function, whose features can be inferred by algebraic handling:

Holes - x-values that do not belong to the domain of the <em>rational</em> function:

x³ + 8 · x² - 9 · x = 0

x · (x² + 8 · x - 9) = 0

x · (x + 9) · (x - 1) = 0

x = 0 ∨ x = - 9 ∨ x = 1

But one root is an evitable discontinuity as:

y = (9 · x² + 81 · x)/(x³ + 8 · x² - 9 · x)

y = (9 · x + 81)/(x² + 8 · x - 9)

Thus, there are only two holes. (x = - 9 ∨ x = 1) Besides, there is no hole where the y-intercept should be.

Vertical asymptotes - There is a <em>vertical</em> asymptote where a hole exists. Hence, the function has two vertical asymptotes.

Horizontal asymptotes - <em>Horizontal</em> asymptote exists and represents the <em>end</em> behavior of the function if and only if the grade of the numerator is not greater than the grade of the denominator. If possible, this assymptote is found by this limit:

y = \lim_{x \to \pm \infty} \frac {9\cdot x + 81}{x^{2}+8\cdot x - 9}

y = 0

The function has a horizontal asymptote.

x-Intercept - There is an x-intercept for all x-value such that numerator is equal to zero:

9 · x + 81 = 0

x = - 9

There is a x-intercept.

Lastly, we have the following conclusions:

  1. How many holes? 2
  2. One <em>horizontal</em> asymptote along the line where y always equals what number: 0
  3. This function has x-intercepts? True
  4. One <em>vertical</em> asymptote along the line where x always equals what number: 1
  5. There is a hole where the y-intercept should be? False

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

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