A normal deck of 52 cards includes 4 suits where each suit ranges from 2 though 10 inclusive, Jack, Queen, King and Ace. In a st
andard deck of 52 cards laying face down, if you select one card from the pile, what is the probability you select a diamond and a face card (jack, queen or king)?
Each suit contains cards of 2-10, and a Jack, Queen, King, and Ace
How to solve:
We need to find the probability of drawing one of 3 diamond face cards, which gives us all of the information we need. Using division, we can create a 'x amount of diamond face cards/y amount of total cards' probability.
<h3>Process:</h3>
Probability of a diamond face card
<em>Where P is the probability of drawing that card, x is the number of diamond face cards, and y is the total amount of cards.</em>
Set up equation P = x/y
Substitute P = (3)/(52)
Answer: 3/52 (~5.77%)
Because there are 3 diamond face cards in the deck, the chance of drawing one is {3 cards out of 52 total}, which is 3/52.
The chance of drawing ANY face card is {(3 per suit, 4 suits=) 12 cards out of 52 total} 12/52 (~23.08%),
The chance of drawing ANY diamond card is {1 suit out of 4 suits} 1/4 (25%)
