Answer:
2÷45 - 76<em><u> </u></em><em><u>and </u></em><em><u>the </u></em><em><u>answer </u></em><em><u>is </u></em><em><u>yours</u></em>
Answer:
f⁻¹(x) = (1/2)x +5
Step-by-step explanation:
In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).
... y = 2x -10
... x = 2y -10 . . . . . . swapped variables
... x +10 = 2y . . . . . add 10
... (1/2)x + 5 = y . . . . divide by 2
... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation
-1. Plug in -3 for x which makes 9-10 so -1
Answer:
Step-by-step explanation:
It's algebra really, basically make a system of equations.
1b+5j=t
3b+2j=2t
I'm gonna solve the first one for buckets so we have it in terms of jars.
b+5j=t
b=t-5j
Now I plug that into the other equation
3b+2j=2t
3(t-5j)+2j=2t
3t-15j+2j=2t
Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other. or it other words solve for t.
3t-15j+2j=2t
3t-13j = 2t
3t = 2t+13j
t = 13j
So it takes 13 jars to make one tub, or one jar is 1/13 of a tub. You could then plug that in to one of the equations and find how much a bucket is.
The question would be:
Which is the best measure of center for first period and why?
Mean, because there are no outliers that affect the center
Median, because there is 1 outlier that affects the center
Interquartile range, because there is 1 outlier that affects the center
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I think the answer would be the fourth choice "</span><span>Standard deviation, because there are no outliers that affect the center"
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I hope my answer has come to your help. God bless and have a nice day ahead!
