Yes
factor out the 2z^2 in each term
(2z^2)(z^2-5z+4)
factor some more
z^2-5z+4
find what 2 numbers multiply to get 4 and add to get -5
the numbers are -1 and -4
(z-1)(z-4)
the factored form is
(2z^2)(z-1)(z-4)
The period of the function is 2pi
The reciprocal of 6/5 is D. 5/6
Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.
We need to get reciprocal of a fraction when division is performed.
For example: 2 ÷ 1/5
2 may be a whole number but in fraction form it is 2/1.
1st fraction = 2/1
2nd fraction = 1/5
In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.
1/5 ⇒ 5/1
Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10
So, 2 ÷ 1/5 = 10
Answer:
Factors: 
Step-by-step explanation:
We are given a polynomial:
We have to factor the given polynomial into its complex factors.
The factorization can be done as follows:
