Question

How does sec(x)-1/tan(x) + tan(x)/sec(x)+1 = 2sin(x)/1+cos(x)

Answer 1

Answer in the attachment.

Used:

$\sec x=\dfrac{1}{\cos x}\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$