Question

Finding Hypotenuse Lengths. Find the length of the hypotenuse in

Answer 1

Answer:

6. $2\sqrt{2}$

7. $7\sqrt{2}$

8. $\sqrt{10}$

9. $8\sqrt{2}$

10. $3$

11. $2\sqrt{5}$

Step-by-step explanation:

for all of these problems i used the pythagorean theorem, which is $a^{2} + b^{2} = c^{2}$

6.

$2^{2} + 2^{2} = c^{2}$

$8=c^{2}$

$\sqrt{8} =\sqrt{c^{2} }$

$2\sqrt{2}$

7.

$7^{2} + 7^{2} = c^{2}$

$49+49=c^{2}$

$98=c^{2}$

$\sqrt{98} =\sqrt{c^{2} }$

$7\sqrt{2}$

8.

$(\sqrt{5})^{2} +(\sqrt{5})^{2} =c^{2}$

$5+5=c^{2}$

$\sqrt{10}$

9.

$8^{2} +8^{2} =c^{2}$

$64+64=c^{2}$

$128=c^{2}$

$\sqrt{128} =\sqrt{c^{2} }$

$8\sqrt{2}$

10.

$(\sqrt{3}) ^{2} + (\sqrt{3}) ^{2} = c^{2}$

$3+3=c^{2}$

$9=c^{2}$

$\sqrt{9} =\sqrt{c^{2} }$

$3$

11.

$(\sqrt{10}) ^{2} + (\sqrt{10}) ^{2} = c^{2}$

$10+10=c^{2}$

$20=c^{2}$

$\sqrt{20} =\sqrt{c^{2} }$

$2\sqrt{5}$