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sergeinik [125]
3 years ago
10

Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated temperatures. CH₄(????) + H₂O(????) ⇌ 3

H₂(????) + CO(????) What is the equilibrium constant for the reaction if a mixture at equilibrium contains gases with the following concentrations: CH₄, 0.126 M; H₂O, 0.242 M; CO, 0.126 M; H₂ 1.15 M, at a temperature of 760 °C?
Chemistry
1 answer:
sammy [17]3 years ago
5 0

Answer:

6.2846

Explanation:

Given that:-

Concentrations at equilibrium :-

[CH_4]=0.126\ M

[H_2O]= 0.242\ M

[CO]= 0.126\ M

[H_2]= 1.15\ M

The equilibrium reaction is:-

CH_4+H_2O\rightleftharpoons 3H_2+CO

The expression for equilibrium constant is:

K_{c}=\frac {\left [ H_2 \right ]^3\left [ CO \right ]}{\left [ CH_4 \right ]\left [ H_2O \right ]}

Applying the values as:-

K_c=\frac{1.15^3\times 0.126}{0.126\times 0.242}=6.2846

<u>The equilibrium constant for the reaction is:- 6.2846</u>

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Answer: Option (B) is the correct answer.

Explanation:

According to Le Chatelier's principle, any disturbance causes in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

For example, 2NO_{2}(g) \rightleftharpoons N_{2}O_{4}(g)

When we increase the temperature then the reaction will shift in a direction where there will be decrease in temperature.

This, means that the reaction will shift in the backward direction.

Thus, we can conclude that if the reaction is at equilibrium and the temperature increases, the equilibrium will shift so that there is more nitrogen dioxide.

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1.55 × 10²⁵ atoms of H  

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3 years ago
How many moles are present in 3.4 x 1023 atoms of Na?
Andrej [43]
<h3><u>moles of H2SO4</u></h3>

Avogadro's number (6.022 × 1023) is defined as the number of atoms, molecules, or "units of anything" that are in a mole of that thing. So to find the number of moles in 3.4 x 1023 molecules of H2SO4, divide by 6.022 × 1023 molecules/mole and you get 0.5646 moles but there are only 2 sig figs in the given so we need to round to 2 sig figs. There are 0.56 moles in 3.4 x 1023 molecules of H2SO4

Note the way this works is to make sure the units are going to give us moles. To check, we do division of the units just like we were dividing two fractions:

(molecules of H2SO4) = (molecules of H2SO4)/1 and so we have 3.4 x 1023/6.022 × 1023 [(molecules of H2SO4)/1]/[(molecules of H2SO4)/(moles of H2SO4)]. Now, invert the denominator and multiply:

<h3 />
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2 years ago
How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
3 years ago
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