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2 years ago

Look at the table. Which of these three substances is not an alloy?

Chemistry

2 answers:

balu736 [363]2 years ago

8 0

Answer:

The correct answer is Letter B

Explanation:

hope it's can help

Gemiola [76]2 years ago

5 0

Answer:

B is the correct option.

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Explain the different melting points between ionic and covalent bonding

yarga [219]

Ionic bonding is formed in Ionic compounds due to electrostatic force between the oppositely charged ions.

In covalent bonds electrons are shared between the atoms. In case of ionic bond the bond is stronger as there is complete transfer of electrons from one ion to the other.

Since the ionic bonds are more difficult to break than the covalent bonds, ionic compounds have a higher melting point than covalent compounds.

5 0

3 years ago

Read 2 more answers

You want to slow down the following reaction:

zimovet [89]

Iron oxide is rust. So oil would be an inhibitor.

4 0

2 years ago

When would you need the fight or flight response?

Naya [18.7K]

Answer:

When you have the feeling of danger and you either don't want to face it or you want to face it.

Explanation:

4 0

3 years ago

The activation energy (E*) for 2N2O ---> 2N2 + O2 is 250 KJ. If the k for this reaction is 0.380/M at 1001oK, what will k be

Sedbober [7]

Answer:

Explanation:

GIven that:

The activation energy = 250 kJ

k₁ = 0.380 /M

k₂ = ???

Initial temperature $T_1 =$ 1001 K

Final temperature $T_2 =$ 298 K

Applying the equation of Arrhenius theory.

$In \dfrac{k_2}{k_1 }= \dfrac{Ea}{R}( \dfrac{1}{T_1 }- \dfrac{1}{T_2})$

where ;

R gas constant = 8.314 J/K/mol

$In \dfrac{k_2}{0.380 }= \dfrac{250 * 10^3}{8,314}( \dfrac{1}{1001 }- \dfrac{1}{298})$

$In \dfrac{k_2}{0.380 }= -70.8655$

$\dfrac{k_2}{0.380 }= e^{-70.8655}$

$\dfrac{k_2}{0.380 }= 1.67303256 \times 10^{-31}$

${k_2}= 1.67303256 \times 10^{-31} \times {0.380 }$

${k_2}= 6.3575 \times 10^{-32}$ /M .sec

Half life:

At 1001 K.

$t_{1/2} = \dfrac{In_2}{k_1}$

$t_{1/2} = \dfrac{0.693}{0.38}$

$t_{1/2} =$ 1.82368 secc

At 298 K:

$t_{1/2} = \dfrac{0.693}{6.3575 \times 10^{-32}}$

$t_{1/2} =1.09 \times 10^{31} \ sec$

3 0

3 years ago

the normal boiling point of ethanol is 78.3 and its molar heat of vaporization is 393. Calculate the vapor pressure of ethanol a

madam [21]

0.12 atm vapor pressure of ethanol at 45.0 C.

What is vapor pressure in science definition?

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.
The temperature at which the vapour pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid.

We will use the Clausius-Clapeyron equation,

ln(P2/P1) = dHvap/R[1/T1-1/T2]

where,

P1 = unknown

P2 = 1 atm

T1 = 30 oC = 30 + 273 = 303 K

T2 = 78.3 oC = 78.3 + 273 = 351.3 K

dHvap = 39.3 kJ/mol = 39300 J/mol

R = 8.314 J/K.mol

Feed values,

ln(1/P1) = 39300/8.314[1/303 - 1/351.3]

P1 = 0.12 atm

thus, the vapor pressure at 30° C is 0.12 atm.

Learn more about vapor pressure

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8 0

1 year ago