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Dimas [21]
4 years ago
5

At what temperature is water at its greatest density​

Chemistry
2 answers:
ahrayia [7]4 years ago
6 0

Answer:

3.98^oC

Explanation:

We usually approximate the density of water to about 1000 kg/m^3 at room temperature. In terms of the precise density of water, this is not the case, however, as density is temperature-dependent.

The density of water decreases with an increase in temperature after the peak point of its density. The same trend might be spotted if the temperature of water is decreased from the peak point.

This peak point at which the density of water has the greatest value is usually approximated to about 4^oC. For your information, I'm attaching the graph illustrating the function of the density of water against temperature where you could clearly indicate the maximum point.

To a higher precision, the density of water has a maximum value at 3.98^oC, and the density at this point is exactly 1000 kg/m^3.

Kazeer [188]4 years ago
4 0
3.98*c is the answer
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8 0
3 years ago
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Một hỗn hợp X gồm CH3OH; C2H5OH; phenol có khối lượng 28,9 gam phản ứng vừa hết với 100ml dung dịch NaOH 2M. Phần trăm theo khối
slavikrds [6]

Answer:

nNaOH = 0,2 mol

Trong hỗn hợp các chất đề bài cho chỉ có phenol tác dụng với NaOH

C6H5OH + NaOH → C6H5ONa + H2O

   0,2  ←     0,2 (mol)

⟹ mphenol = 0,2.94 = 18,8 gam

⟹  

%mC6H5OH=18,8/28,9 x100%= 65,05%

Explanation:

3 0
3 years ago
If the unknown elements on the periodic table are "unknown" how did they end up in the periodic table in the first place? *think
mezya [45]

Answer:

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Explanation:

8 0
4 years ago
how many grams of ammonium carbonate are needed to decompose in order to produce 6.52 g of carbon dioxide?
defon

Answer:

<u>= 14.24g of </u>(NH4)_{2}CO_{3}<u> is required.</u>

Explanation:

Reaction equation:

(NH4)_{2}CO_{3} → 2NH_{3} + CO_{2} + H_{2} O

Mole ratio of ammonium carbonate to carbon dioxide is 1:1

1 mole of CO2 - 44g

?? mole of CO2 - 6.52g

= 6.52/44 = 0.148 moles was produced from this experiment.

Therefore, if 1 mole of (NH4)_{2}CO_{3} - 96.09 g

0.148 mol of (NH4)_{2}CO_{3} --  ?? g

=0.148 × 96.09

<u>= 14.24g of </u>(NH4)_{2}CO_{3}<u> is required.</u>

5 0
3 years ago
At a certain temperature, the equilibrium constant, K c , for this reaction is 53.3. H 2 ( g ) + I 2 ( g ) − ⇀ ↽ − 2 HI ( g ) K
swat32

Answer:

[HI]_{eq}=0.942M

Explanation:

Hello,

In this case, the initial concentrations of hydrogen and iodine are the same:

[H_2]_0=[I_2]_0=0.600M

Thus, considering the given undergoing chemical reaction, one states the law of mass action in terms of the change x due to the chemical change as shown below:

Kc=\frac{(2x)^2}{(0.600M-x)(0.600M-x)}=53.3

Therefore, solving for x by quadratic equation one obtains:

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Nevertheless, the feasible result is the first one as the second one results in negative concentrations, thus, the hydroiodic acid equilibrium concentration turns out:

[HI]_{eq}=2*0.471M=0.942M

Best regards.

8 0
3 years ago
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