Explanation:
We know that,
Where,
h = Height at which pressure is to be calculated
R = 2700 ohm
I = 2.4 mA = 2.4 × 10^(-3) A
I = Q/t
Q = I × t = 2.4 × 10^(-3) × 15 s = 36 C
Answer:
The magnitude of the average frictional force on the block is 2 N.
Explanation:
Given that.
Mass of the block, m = 2 kg
Initial velocity of the block, u = 10 m/s
Distance, d = 50 m
Finally, it stops, v = 0
Let a is the acceleration of the block. It can be calculated using third equation of motion. It can be given by :
The frictional force on the block is given by the formula as :
F = ma
|F| = 2 N
So, the magnitude of the average frictional force on the block is 2 N. Hence, this is the required solution.
Explanation:
The object is moving along the parabola y = x² and is at the point (√2, 2). Because the object is changing directions, it has a centripetal acceleration towards the center of the circle of curvature.
First, we need to find the radius of curvature. This is given by the equation:
R = [1 + (y')²]^(³/₂) / |y"|
y' = 2x and y" = 2:
R = [1 + (2x)²]^(³/₂) / |2|
R = (1 + 4x²)^(³/₂) / 2
At x = √2:
R = (1 + 4(√2)²)^(³/₂) / 2
R = (9)^(³/₂) / 2
R = 27 / 2
R = 13.5
So the centripetal force is:
F = m v² / r
F = m (5)² / 13.5
F = 1.85 m
According to the solving, the volume that this gold nugget occupies is 1.29 cm³.
<h3>What is volume?</h3>
Volume is a standard measure of three-dimensional space that is occupied. It is typically mathematically represented using standard or SI-derived units. Volume and the concept of length are connected. It is sometimes referred to as the object's capacity.
d= m/ V
m= dV
V= m/d
<h3>So according to the given data,</h3>
The mass of the gold nugget is 25 grams.
The density of gold is 19.32 g/cm³.
We know that,
m= Vd
To find out the Volume(V),
V= m/d
V= (25 g)/(19.32 g/cm³)
V= 1.29 cm³.
According to the solving, the volume this gold nugget occupies is 1.29cm³.
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