All categories

3 years ago

How does the distance between the car and launcher affect the speed of the car?

1 answer:

lisabon 2012 [21]3 years ago

3 0

The effect of the distance of a launcher affects the speed of a car in that an optimum distance is desirable for optimal performance.

If the distance is too small the speed of the car will be minimal, also of the distance is too large, the speed of the car will be small also.

Hence, the speed is optima only when we have an optima distance in between.

Learn more about the speed of the car and distance here:

brainly.com/question/111325

You might be interested in

A child bouncing a ball. Which law of motion does the situation describe?

vlada-n [284]

Kinetic energy evades the ball jumping higher than the kid

7 0

3 years ago

You pull a wagon with a force of 20 N. The wagon has a mass of 10 kg. What is the wagon's acceleration?

Nana76 [90]

Answer:

<h3>The answer is 2 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

where

f is the force

m is the mass

From the question

f = 20 N

m = 10 kg

We have

$a = \frac{20}{10} \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equa

ivann1987 [24]

Answer:

The moment of inertia of the wheel is 0.593 kg-m².

Explanation:

Given that,

Force = 82.0 N

Radius r = 0.150 m

Angular speed = 12.8 rev/s

Time = 3.88 s

We need to calculate the torque

Using formula of torque

$\tau=F\times r$

$\tau=82.0\times0.150$

$\tau=12.3\ N-m$

Now, The angular acceleration

$\dfrac{d\omega}{dt}=\dfrac{12.8\times2\pi}{3.88}$

$\dfrac{d\omega}{dt}=20.73\ rad/s^2$

We need to calculate the moment of inertia

Using relation between torque and moment of inertia

$\tau=I\times\dfrac{d\omega}{dt}$

$I=\dfrac{I}{\dfrac{d\omega}{dt}}$

$I=\dfrac{12.3}{20.73}$

$I= 0.593\ kg-m^2$

Hence, The moment of inertia of the wheel is 0.593 kg-m².

5 0

3 years ago

Which material is the MOST dense?<br><br> A. lead<br> B. brick<br> C. copper<br> D. platinum

Murljashka [212]

I think platinum is most dense

7 0

4 years ago

Read 2 more answers

One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi

Masteriza [31]

Answer:

a) $S_1=-9.65}\ J/K$

b) $S_2=71.18\ J/K$

c) 0 J/K

d)S= 61.53 J/K

Explanation:

Given that

T₁ = 745 K

T₂ = 101 K

Q= 7190 J

The entropy change of reservoir 745 K

$S_1=-\dfrac{7190}{745}\ J/K$

Negative sign because heat is leaving.

$S_1=-9.65}\ J/K$

The entropy change of reservoir 101 K

$S_2=\dfrac{7190}{101}\ J/K$

$S_2=71.18\ J/K$

The entropy change of the rod will be zero.

The entropy change of the system

S= S₁ + S₂

S = 71.18 - 9.65 J/K

S= 61.53 J/K

3 0

4 years ago