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nevsk [136]
3 years ago
7

) Water falls from a height of 60m at the rate of 15kg/s to operate a turbine. The losses due to frictional force are 10% of ene

rgy. How much power in generated by the turbine?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

8100W

Explanation:

Let g = 10m/s2

As water is falling from 60m high, its potential energy from 60m high would convert to power. So the rate of change in potential energy is

P = \dot{E} = \dot{m}gh = 15*10*60 = 9000 J/s or 9000W

Since 10% of this is lost to friction, we take the remaining 90 %

P = 9000*90% = 8100 W

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What is the internal energy of 4.50 mol of N2 gas at 253°C? To solve this
Finger [1]

The internal energy of the gas is 49,200 J

Explanation:

The internal energy of a diatomic gas, such as N_2, is given by

U=\frac{5}{2}nRT

where

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

n = 4.50 (number of moles)

R = 8.31 J/(mol·K) (gas constant)

T=253^{\circ} + 273 = 526 K (absolute temperature)

Substituting, we find:

U=\frac{5}{2}(4.50)(8.31)(526)=49,200 J

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6 0
3 years ago
The velocities of light in air and glass are 3.0 x 10^8ms and 2.0×10^8ms respectively. If the angle of refraction is 30°, the si
JulijaS [17]

Answer:

0.75

Explanation:

refractive \: index \:  =  \frac{3.0 \times  {10}^{2} }{2.0 \times  {10}^{2} }

= 1.5

refractive \: index =  \frac{ \sin(angle \: of \: incidence) }{ \sin(angle \: of \: refraction) }

1.5 =  \ \frac{ \sin(i) }{ \sin(30) }

1.5 × ½ = sin(i)

\sin(i)  =  0.75

5 0
3 years ago
Mass m moves to the right with speed =v along a frictionless horizontal surface and crashes into an equal mass m initially at re
Amiraneli [1.4K]

After the collision the magnitude of the momentum of the system is Mv

Given:

mass of 1st object = M

speed of 1st object = v

mass of 2nd object = M

speed of 2nd object = 0

To Find:

magnitude of the momentum after collision

Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.

Applying conservation of linear momentum

Mv + M(0) = 2MV

Mv = 2MV

V = v/2

So, after collision momentum is

p = 2MV = 2xMxv/2 = Mv

So, after collision momentum is Mv

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4 0
2 years ago
What's an acrostic poem for climate each line has to be written in a full sentence?
Mrac [35]
Acrostic poem is a poem where the initials of the main word is given a respective sentence starting with that initial.
C- Can you see any changes happened in our surrounding?
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M- Making a move? Let's start it now.
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E- Even to smallest thing that we can share.
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In the diagram, the wavelength is shown by :
MAXImum [283]

Answer:

i think the anwer is C

Explanation:

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