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nevsk [136]
3 years ago
7

) Water falls from a height of 60m at the rate of 15kg/s to operate a turbine. The losses due to frictional force are 10% of ene

rgy. How much power in generated by the turbine?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

8100W

Explanation:

Let g = 10m/s2

As water is falling from 60m high, its potential energy from 60m high would convert to power. So the rate of change in potential energy is

P = \dot{E} = \dot{m}gh = 15*10*60 = 9000 J/s or 9000W

Since 10% of this is lost to friction, we take the remaining 90 %

P = 9000*90% = 8100 W

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A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular accelera
nalin [4]

Answer:

5.74s

Explanation:

We can first solve for the initial angular velocity using the following formula

\omega^2 - \omega_0^2 = 2\alpha\theta

Where \omega = -22.4rad/s is the final angular velocity, \alpha = -22.4 rad/s^2is the angular acceleration and \theta = 0 is the angular displacement

22.4^2 - \omega_0^2 = 2*(-7.8)*0

\omega_0^2 = 22.4^2

\omega_0 = 22.4rad/s

So for the wheel to get from 22.4 to -22.4 with angular acceleration of -7.8 then the time it takes must be

t = \frac{\Delta \omega}{\alpha} = \frac{-22.4 - 22.4}{-7.8} = 5.74s

8 0
3 years ago
Consider a uniform sphere, which has a mass of 4.80 kg and a radius of 22.0 cm. A tangential force of 11.2 N is applied to the o
Tcecarenko [31]

Answer:

The moment of inertia of this sphere is 0.0929\ kg-m^2.                  

Explanation:

It is given that,

Mass of the sphere, m = 4.8 kg

Radius of the sphere, r = 22 cm = 0.22 m

Tangential force, F = 11.2 N

The moment of inertia of the uniform sphere is given by :

I=\dfrac{2}{5}mr^2

I=\dfrac{2}{5}\times 4.8\ kg\times (0.22\ m)^2

I=0.0929\ kg-m^2

So, the moment of inertia of this sphere is 0.0929\ kg-m^2. Hence, this is the required solution.              

8 0
3 years ago
A mass m1= 6.20 kg is moving North with a velocity of v1= 13.5m/sec when it collides perpendicularly with another mass m2= 4.40
JulijaS [17]

Answer:

Momentum of mass m_{1} is 83·7 kg m/s towards north

Momentum of mass m_{2} is 38·72 kg m/s towards east

Explanation:

Given

Mass of m_{1} = 6·2 kg

Mass of m_{2} = 4·4 kg

Velocity of mass m_{1} = v_{1} = 13·5 m/s

Velocity of mass m_{2} = v_{2} = 8·8 m/s

Momentum of mass m_{1} = m_{1} × v_{1} = 6·2 × 13·5 = 83·7 kg m/s

Momentum of mass m_{2} = m_{2} × v_{2} = 4·4 × 8·8 = 38·72 kg m/s

As mass m_{1} is moving North, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity

As mass m_{2} is moving East, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity

∴ Momentum of mass m_{1} is 83·7 kg m/s towards north

∴ Momentum of mass m_{2} is 38·72 kg m/s towards east

7 0
3 years ago
What would you expect to happen to the acceleration if all friction were removed from the ramp, making the net force even higher
marta [7]

Answer:

Make on your answer!

Explanation:

Naara sa module ang answer Anna..

3 0
3 years ago
A negative charge, q1, of 6 µC is 0. 002 m north of a positive charge, q2, of 3 µC. What is the magnitude and direction of the e
prohojiy [21]

Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

<h3>What is electrical force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is

q₁ is the negative charge = 6 µC=6×10⁻⁶ C

q₂ is the positive charge = 3 µC=3×10⁻⁶ C

r is the distance between the charges=0.002 m

F_E is the electric force =?

The value of electric force will be;

\rm F_E= \frac{Kq_1q_2}{r^2} \\\\ F_E= \frac{9\times 10^9\times 6\times 10^{-6}\times3\times10^{-6}}{(0.002)^2}\\\\ \rm F_E=4.05\times10^4\;N

Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

To learn more about the electrical force refer to the link;

brainly.com/question/1076352

7 0
2 years ago
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