Answer:
maybe they are about to visit you or kill you or maybe something else
The answer to this question is letter B
Answer: See attached table
Step-by-step explanation:
![\begin{table}[]\begin{tabular}{lllll} & & & & \\ & & & & \\ & & & & \\ & & & & \end{tabular}\end{table}](https://tex.z-dn.net/?f=%5Cbegin%7Btable%7D%5B%5D%5Cbegin%7Btabular%7D%7Blllll%7D%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%5Cend%7Btabular%7D%5Cend%7Btable%7D)
+---+---+---+
| 1 | 8 | 2 |
+---+---+---+
| 6 | 4 | 2 |
+---+---+---+
| 5 | 0 | 7 |
+---+---+---+
<u>Proofs:</u>
First row: 1+6+5 = 12
Second row: 8+4+0 = 12
Third row: 2+2+7 = 12
First column: 1+8+2 = 12
Second column: 6+4+2 = 12
Third column: 5+0+7 = 12
Diagonal starting from top left to bottom right: 1+4+7 = 12
Diagonal staring from top right to bottom left: 2+4+5 = 12
Answer:
Step-by-step explanation:
Your exponential formula is in the form y = ab^x. In this form, the coefficient 'a' is the initial value, the y-intercept, the value when x=0. The value 'b' is the growth factor, which is 1 more than the growth rate per increment of x. This problem is asking for the growth rate to be expressed as a percentage.
__
Given p(x) = 78500(1.02^x), we can compare to the exponential function form to see that ...
- a = 78,500
- b = 1.02 = 1 +0.02 = 1 +2%
The value of x is zero in the year 2000, so the population that year is ...
p(0) = a = 78,500
The increase per year is the value of 'b' with 1 subtracted:
growth rate = 2% per year
Answer:
A unit rate is a rate where the second quantity is one unit , such as $34 per pound, 25 miles per hour, 15 Indian Rupees per Brazilian Real, etc. 1 minute=60 seconds1 hour=60 minutes (or) 3600 seconds1 day=24 hours (or) 1440 minutes.
Step-by-step explanation:
