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kvv77 [185]
3 years ago
11

Solve by factoring:x^2+4x-12=0

Mathematics
1 answer:
Alika [10]3 years ago
8 0
X^2+4x-12=0
(x+6)(x-2)=0
X can equal -6 and 2.

x=-6
x=2
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Can someone help me work through this ??
S_A_V [24]
The interpretation of the solution is that there are 15 true/false questions and 5 multiple choice questions.
3 0
3 years ago
Which statement is true?
Wittaler [7]

Answer:

The y-intercept of Function A is less than the y-intercept of Function B.

Step-by-step explanation:

Function A's y-intercept would be (0, -1) and Function B's y-intercept is (0, 4). Therefore, Function A's y-intercept is less than Function B's.

5 0
2 years ago
Graph the line y = -2x - 2
Daniel [21]

Answer:

-2x-2

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Step-by-step explanation:

graph is inserted

8 0
2 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
2 years ago
Whats the area of a polygon with vertices A(2,3) B(12,3) C(6,0) and D(2,0)
Vanyuwa [196]
This shape is trapezoid

top of the trapezoid is 10 (12-2)

and the bottom is 4 (6-2)

the height in 3 (3-0)


so the area will be
((10+4)  \times 3) \div 2  \\  = (14 \times 3)  \div 2 = 42 \div 2 \\  = 21
the area is 21
6 0
3 years ago
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