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ycow [4]
3 years ago
6

Do alto de um farol cuja altura é de 20 m avista se um navio sob ângulo de depressão de 30°. A que distância , aproximadamente,

o navio se acha do farol ?

Mathematics
1 answer:
Mkey [24]3 years ago
7 0
Esta é a trigonometria . Se você desenhar uma linha a partir do topo da casa de luz para o barco, você terá a hypotonuse de um triângulo. Um truque é lembrar que este é um triângulo especial. É um triângulo 30-60-90 , que tem propriedades especiais mostradas na fixação abaixo . por isso sabemos que o lado adjacente que não é o hyposonuse é x√3 . Agora sabemos que x<span>√3 = 20
Solve for x.
x</span><span>√3=20
divide both sides by </span><span>√3.
x=20/(</span><span><span>√3)
</span>Try not to have square roots (</span><span><span>√)</span> in denomenator so multiply top and bottom by </span><span>√3 and get
x=(20</span><span>√3)/3
x is what we are looking for so the answer is </span>
20<span>√3 m </span><span>ou cerca de 34.64 m</span>










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Please help it is math
olasank [31]

Answer:

A linear function has the form y=mx+b

A line has a proportional relationship if y/x is always the same ratio for any value.

The slope m=(y2-y1)/(x2-x1) for some two points on a line is always constant, else it wouldn't create a line.

A line won't be proportional if you adapt b because the ratio of y/x won't match the slope anymore.

In the end this means all lines with proportional relationships must intersect (0,0) or in other words f(0)=0.

This happens if they have the shape y=mx.

Step-by-step explanation:

hope this helps pls mark me brainliest

4 0
2 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
If the original quantity is 14 and the new quantity is 22, which of these is the best estimate for the percent of change?
julsineya [31]
D 22-14=8 14-7=7 7 of 14=50% so i think that’s the best estimate
8 0
2 years ago
The cost of 15 orange is Rs 75. How much price of 12 oranges​
stira [4]

1. The price of 3 metres of cloth is Rs 79.50. Find the price of 15 metres of such cloth. Solution: It is given that. Price of 3 m of cloth = Rs 79.50. We get. Price of 1 m of cloth = 79.50/3 = Rs 26.5. So the price of 15 m of cloth = 26.5 (15) = Rs 397.50. Hence, the price of 15 m of such cloth is Rs 397.50. 2. The cost of 17 chairs is Rs 9605.

Estimated Reading Time: 4 mins

4 0
2 years ago
Read 2 more answers
Pls answer quick I will give bainlyest to first GOOD answer
Helen [10]

Answer:

R1 - given

R2 - subtraction property of equality

R3 - distribution

S4 - 9x = 61

R5 - division prop. of equality

Step-by-step explanation:

hope this helps :)

5 0
3 years ago
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