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3 years ago

See your levels

1 answer:

7 0

Answer:
3 postcards

Explanation:
So the question says that Brenna bought 4 packs of 12 postcards, which is the same as 4x12.

4x12=48, so Brenna bought 48 postcards.

It says that she only needed 45, so we can subtract 45 from 48.

48-45=3

Brenna had three postcards left over.

Hope this helped you!

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Which table represent a linear function

andrew-mc [135]

The first one it goes up in the same increments

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3 years ago

A farmer collected 12 dozen eggs from her chickens. She sold 5/6 of the eggs to the farmers market and gave the rest to friends

Aleks [24]

Multiply 12 x 12 which is 144. And then you divide that by 6 and you get 24

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3 years ago

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Write an equation of the line in slope-intercept form. (Pls answer fast)<br><br> Y=

nydimaria [60]

Answer:

$y = - \frac{1}{4} x + 3$

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3 years ago

A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the

Kay [80]

Answer: The required number of quarters in the collection is 11.

Step-by-step explanation: Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05, 1 dime = $ 0.10 and 1 quarter = $0.25.

Then, according to the given information, we have

$x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

$(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)$

and

$y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Comparing the values of y from equations (iv) and (v), we get

$47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.$

Thus, the required number of quarters in the collection is 11.

7 0

3 years ago

A right triangle has one 64degree angle and one 90 degree angle

melamori03 [73]

Answer:

I dont know what your asking, for the other angle? Ig so. Answer: THE OTHER ANGLE IS 26. :)

Step-by-step explanation:

64 + 90 = 154.

All triangles add up to 180 degrees.

180-154 = 26.

7 0

3 years ago