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8090 [49]
2 years ago
11

Welcome to Gboard clipboard, any text you copy will be saved here.​

Mathematics
1 answer:
Dafna11 [192]2 years ago
4 0

Answer:

yooo i got the new rank im now expert :0

Step-by-step explanation:

XD

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HELPP HELP. It’s about slope!!!! Explanation needed
OleMash [197]

Answer:

<em> x = -3</em>

Step-by-step explanation:

A line has equation: y = ax + b

This line has slope a = 1

This line passes (4, 1)

=> 1 = 4 + b

=> b = -3

=> The equation of this line : y = x - 3

This line passes another point (x, -6)

=> -6 = x - 3

=> x = -6 + 3

=> x = -3

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3 years ago
A theater company made 6,000 programs for their current play. The play will have 20 performances. If they would like to have the
VashaNatasha [74]
Divide 6000 by 20
= 300 programs for each perfomance

5 0
3 years ago
What are the coordinates of point B?
tatyana61 [14]

Answer:

C

Step-by-step explanation:

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7 0
3 years ago
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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