If you have two equations, you will multiply one of them so it cancels out the other one. For Example, 2x-y=16 3x-y=28You will multiply the second equation by -1 which brings us to 2x-y=16 -3x+y=-28you will add both equations together which will leave you with-x=-12x=12Then, you plug that in. 2x12=24. 24-16=8. 3x12=36 36-8=28 And, You're done!
Answer:
Step-by-step explanation:
2(2x+7) = 6x-8
4x + 14 = 6x - 8
2x = 22
x = 11
m<XYZ = 58
m<XYW = 29
<u>Answer:
</u>
Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
<u>
Solution:
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Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
Answer:
<h2>Yes the circumference is about times greater than their diameters</h2>
Step-by-step explanation:
We will approach this problem by doing a check
Say the diameter of a circle is 4 cm
Hence the radius is 3 cm
We know that the circumference is 
The circumference is about 3 time bigger than the diameter
Let us try another case say the diameter is 6 cm
The radius is 3 cm
