Answer:
A. 444.5 pm
Explanation:
We know that:
i.e.
in a face-centered cubic crystal, the number of atoms per unit cell is (n) = 4
The molar mass of manganese (II) oxide ![[Mn(11)O] = 70.93 \ g/mol](https://tex.z-dn.net/?f=%5BMn%2811%29O%5D%20%3D%2070.93%20%5C%20g%2Fmol)
Density 
is given as 5.365 g/cm³
Avogadro constant 
= 6.023 × 10²³ atoms/mol
∴
Making th edge length "a" the subject, we get:
![a= \sqrt[3]{8.78 \times 10^{-23} \ cm^3}](https://tex.z-dn.net/?f=a%3D%20%5Csqrt%5B3%5D%7B8.78%20%5Ctimes%2010%5E%7B-23%7D%20%5C%20cm%5E3%7D)
a = 4.445 × 10⁻⁸ cm
a = 444.5 pm
Answer:
163 kilograms per cubic feet.
Explanation:
To solve this problem, first we <u>convert 5.77 g/cm³ to kg/cm³</u>:
- 5.77 g/cm³ *
= 5.77x10⁻³ kg/cm³
Then we <u>convert kg/cm³ to kg/ft³</u>, by <em>converting cm³ to ft³</em>:
- 5.77x10⁻³ kg/cm³ *
= 163 kg/ft³
So the density is 163 kilograms per cubic feet.
We have this
<span>C M = n / V => n = C M . V = 0,25 . 0,4 = 0,1 mole </span>
<span>m Na2CO3 = n . M = 0,1 . 106 = 10,6 g</span>
Answer:
Hello friends
Explanation:
<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>
<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>
<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>
<h3>Hope it's helpfully. </h3>
The acid dissociation constant is 1.3 × 10^-3.
<h3>What is acid-dissociation constant?</h3>
The acid-dissociation constant is a constant that shows the extent of dissociation of an acid in solution. We have to set up the reaction equation as shown below;
Let the acid be HA;
HA + H2O ⇄ H3O^+ + A^-
since the pH of the solution is 2.57 then;
[H3O^+] = Antilog(-pH) = Antilog(-2.57) = 2.7 × 10^-3
We can see that; [H3O^+] = [A^-] so;
Ka = (2.7 × 10^-3)^2/(5.5 × 10^–3)
Ka = 1.3 × 10^-3
Learn more about acid-dissociation constant: brainly.com/question/9728159
