Answer:
Solution given:
e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide
Solution given:
<u>Balanced</u><u> </u><u>chemical</u><u> </u><u>equation</u><u>:</u>

<u>when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide</u>
<u>f</u>) chromium (III) hydroxide plus sulfuric acid
<u>Balanced chemical equation:</u>

<u>When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.</u>
g) aluminum metal plus chlorine gas

<u>When aluminum metal is added to chlorine gas</u><u> </u><u>Combination reaction takes place and forms aluminum chloride.</u>
Answer:
its 19 I'm pretty sure about
Answer:
3.3535 g
Explanation:
Considering:
Or,
Given :
For iron(III) nitrate :
Molarity = 0.404 M
Volume = 52.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 52.0×10⁻³ L
Thus, moles of iron(III) nitrate :
Moles of iron(III) nitrate = 0.021 moles
1 mole of iron(III) nitrate forms 1 mole of iron(III) hydroxide which further forms 1 mole of iron(III) oxide.
Thus, moles of iron(III) oxide formed from 0.021 moles of iron(III) nitrate = 0.021 moles
Also, molar mass of iron(III) oxide = 159.69 g/mol
So, mass of iron(III) oxide = 0.021 moles × 159.69 g/mol = 3.3535 g
Lose an electron to form an ion