Answer:
199920J
Explanation:
Given parameters:
Mass of steam = 85g
Unknown:
Heat released when the liquid is condensed = ?
Solution:
The heat released by the substance is given as;
H = mL
H is the heat released
m is the mass
L is the latent heat of steam = 2352J/g
Heat released = 85 x 2352 = 199920J
Answer:
the correct option would be:
The group of response options implies a reduction in the intensity of the workouts with a corresponding increase in the percentage of carbohydrate intake for several days before a competition.
Since the carbohydrate load is an increase in glycogen reserves as an energy source accompanied by a decrease in muscle demand. This is often used in high-performance activities, where strict competencies are required.
Although today some professionals do not support that, but rather support a diet with carbohydrates and proteins.
Explanation:
Carbohydrate loading increases glycogen reserves, it is accompanied by a muscle rest plan, without fatigue of muscle fibers.
The purpose of this is to exhaust the muscle fibers in maximum demands such as the competencies, ensuring a necessary energy source that supplies this reaction, for which glycogen reserves are needed.
The formula for K+ and S-2 is K2S because you need 2 potassium ions to balance out the sulfide ion
Answer:
This is heating limestone
Explanation:
Process:
limestone is heated strongly. After a while, the limestone begins to go cloudy. Test tube is heated too much that it is beginning to soften it. After removing limewater, test tube cools down, the pressure in the test tube drops and air pressure pushes the cold the liquid into the hot test tube with terrible result.
Products:
Limestone is also known as calcium carbonate and Limewater
Click on the link provided to show the video
https://youtu.be/RLL5rT_DeKc
or search heating calcium carbonate
you will find a video
Answer:
Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V
Explanation:
A close look at all the options shows that the most feasible first reaction is the reduction of tin II ion to ordinary metallic tin.
Given the two half cells, nickel is oxidized in one half cell to Ni II while in the second half cell, tin II ion is reduced to metallic tin. The platinum electrodes simply act as electron conduits in the cell.
