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Drupady [299]
2 years ago
13

Which set of numbers gives the correct possible values of I for n = 22

Chemistry
1 answer:
Alexandra [31]2 years ago
4 0

Answer:

Hello friends

Explanation:

<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>

<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>

<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>

<h3>Hope it's helpfully. </h3>
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18.2 mL of a 0.156 M solution of lead(II) nitrate are added to 26.2 mL of a 0.274 M solution of potassium iodide.
kow [346]

The mass of the Pbl2 : 1308.87

<h3>Further explanation</h3>

Given

18.2 mL of a 0.156 M Pb(NO3)2

26.2 mL of a 0.274 M KI

Reaction

Pb(NO3)2 (aq) + 2 KI (aq) - Pbl2 (s) + 2 KNO3

Required

the mass of the Pbl2

Solution

mol Pb(NO3)2 = 18.2 x 0.156 = 2.8392 mlmol

mol KI = 26.2 x 0.274 =7.1788 mol

Limiting reactant Pb(NO3)2(smaller ratio of mol : reaction coeffiecient)

mol Pbl2 based on limiting reactant (Pb(NO3)2)

From equation, mol ratio of Pb(NO3)2 : Pbl2 = 1 : 1, so mol Pbl2=mol Pb(NO3)2=2.8392

Mass Pb(NO3)2 :

\tt mass=mol\times MW\\\\mass=2.8392\times 461\\\\mass=1308.87~grams

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