All categories

3 years ago

5 points Provide the BALANCED Equation below: * C6H12O6+ O2 + CO2 + H2O

Chemistry

1 answer:

slava [35]3 years ago

4 0

Answer:

C6H12O6+6O2->6CO2+6H2O

Explanation:

You need to start in for the given Questions think in a way what will you need a number for fit to the chemical name. I would suggest if you need practice because sometimes it goes higher when you are chemistry student especially involved in fraction. Thank you for listening

You might be interested in

Does the reaction of a burning candle give off or absorb heat

NemiM [27]

The reaction of a burning candle gives off heat and is an exothermic reaction. It does not absorb heat because it does not cool down its surroundings as the candle burns. The answer is the reaction of a burning candles gives off heat.

6 0

3 years ago

SOMEONE PLEASE HELP ME THIS IS DUE TOMORROW!! I WILL MARK YOU AS A BRAINLIEST IF ANSWERED NOW!!

AnnZ [28]

K= [Ar] 4s^1

Pb= [Xe] 6s^2 5d^10 6p^2

Sc= [Ar] 4s^2 3d^1

Ra= [Rn] 7s^2

O= [He] 2s^2 2p^4

Ag= [Kr] 5s^2 4d^9

Ru= [Kr] 5s^1

Ce= [Xe] 6s^2 5d^1 4f^1

I= [Kr] 5s^2 4d^10 5p^5

F= [He] 2s^2 2p^5

6 0

4 years ago

g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o

Liono4ka [1.6K]

Answer:

pOH = 0.36

Explanation:

Both potassium hydroxide and lithium hydroxide solutions are strong bases, so you assume 100% dissociation.

1. Potassium hydroxide solution, KOH

Volume, V = 304 mL = 0.304 liter

Molarity, M = 0.36 M

number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol

1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

2. LIthium hydroxide, LiOH

Volume, V = 341 mL = 0.341 liter

Molarity, M = 0.51 M

number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol

1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

3. Resulting solution

Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

4. pOH

$pOH=-\log [OH^-]=-\log (0.439)=0.36$ ← answer

5 0

3 years ago

Determine the ph of a 0.188 m nh3 solution at 25°c. the kb of nh3 is 1.76 × 10-5.

Ber [7]

When NH3 is dissolved in water, it dissociates partially producing NH4+ ions and OH- ions. It has an equation:
NH3 + H2O → NH4+ + OH-

We use the Kb expression to determine the [OH-] concentration,

Kb = [NH4+] [OH-] /* [NH3] 

We can write NH4+ as OH- since they are of equal ratio.
(1.76*10^-5) = [OH-]² / 0.188
[OH-]² = 3.3088*10^-6 
[OH-] = 1.819*10^-3 

We calculate for H+ concentration as follows:

[H+] [OH-] = 10^-14 
[H+] = 10^-14 / [OH-] 
[H+] = 10^-14 / (1.819*10^-3) 
[H+] = 5.50*10^-12 

pH = -log [H+] 
pH = -log (5.5*10^-12) 
pH = 11.26

4 0

3 years ago

People sitting around a campfire are able to feel the heat from the fire. How are the people able to feel the heat from the fire

ivanzaharov [21]

People can feel it because of the Thermal energy.

4 0

3 years ago

5 points Provide the BALANCED Equation below: * C6H12O6+ O2 + CO2 + H2O​

5 points Provide the BALANCED Equation below: * C6H12O6+ O2 + CO2 + H2O