Answer:
Step-by-step explanation:
Because we have to rewrite this equation in the format 
, we have to divide, or factor to find basic terms,
Expanding the value of k(x), we have 
. We see that each term can be divisible by 4, so we can factor out 4 to get
Now, we have two different terms getting multiplied. We can separate the two to get 
Because we are multiplying 4 by the other term, this is represented by 
Now, we can just set f(x) and g(x) to these functions:
Now, just to make sure, we can plug a value into k(x) and the same value into f(g(x)). Plugging in 1, we have (2(1)+4)2 as 2(2+4), which is 2(6) = 12.
Plugging 1 into f(g(x)), we can evaluate g(1) first, to get 1 + 2 = 3. Now, f(3) = 4(3)= 12, which is the same for k(x).
Answer:
A A AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
5:20 + 1:35 is 6:55, not 6:40/
1) the x-coordinate of the system can be given as follow:
2x+3y = 5 (i)
3x+5y =7 (ii)
we multiply (i) by 5 and (ii) by 3, we have
10x+15y = 25 (a)
9x+15y =21 (b)
so (a) - (b) implies x = 4,
2) We do the same method for
{2x + y = 2
{3x + 4y = -22,
and we found y = -10,
3) for the last one,
{5x + 4y = 2
{-2y = 8 + 4x
this system is equivalent to
{5x + 4y = 2 (i)
{4x + 2y = - 8 (ii)
so, multiply (i) by 4 and (ii) by 5, and we have
20x + 16y = 8 (a)
20x + 10y = -40 (b)
elimination of x gives 6y = 48 then y= 8, we can find x fastly by replacing y=8 in (i), so 5x +4(8) =2, which implies x= -6
finally the solution is S= {(-6, 8)}
When you take the square root of 11, the result is neither a terminating nor a repeating decimal. Therefore, it is: 2. <u>irrational number</u>.
<h3>The types of numbers.</h3>
In Mathematics, there are six (6) common types of numbers and these include the following:
- Natural (counting) numbers
- Whole numbers
- Rational numbers
- Irrational numbers
- Real numbers
- Integers
<h3>What is an irrational number?</h3>
An irrational number can be defined a type of number which comprises non-terminating or non-repeating decimals such as the square root of 11.
In conclusion, when you take the square root of 11, the result is neither a terminating nor a repeating decimal. Therefore, it is an <u>irrational number</u>.
Read more on irrational number here: brainly.com/question/20400557
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