Volume of cone=(1/3)hpir^2
d/2=r
d=2
d/2=2/2=1=r
h=6
V=(1/3)6pi1^2
V=2pi in^3 is volume
ratio of 2:1
2+1=3
2pi=3 units
divide both sides by 3
2/3pi=1 unit
vanila=2 units
times 2/3pi by 2
4/3pi
aprox pi=3.141592
4.188
round
4.2 in^3 of vanilla
The answer would be
4
5
6
Yes
Answer:
To find the volume of a triangle pyramid, you would use the formula V = 1/3AH, where A = area of the triangle base, and H = height of the pyramid or the distance from the pyramid's base to the apex.
Hope this helps!!
Sorry for the hand writing. But you want to factor out a 4y^2 which will result in (9y^2-1). Then you will factor out the equation in parentheses to (3y-1)(3y+1). Don’t forget to put the 4y^2 out front!
Answer:
(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)
Here we have the equation:

We can rewrite this as:

Now we can add and subtract cos^2(x)*sin^2(x) to get:

We can complete squares to get:

and we know that:
cos^2(x) + sin^2(x) = 1
then:

This is the closest expression to what you wrote.
We also know that:
sin(x)*cos(x) = (1/2)*sin(2*x)
If we replace that, we get:

Then the simplification is:
