3 years ago

4 times as much as 3 is

Mathematics

2 answers:

BabaBlast [244]3 years ago

7 0

Answer:

Step-by-step explanation:

4x3=12

inysia [295]3 years ago

4 0

12 four times three is 12

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Hi!

suter [353]

Answer:

1 median=60.3

2 missing number=38

Step-by-step explanation:

1 45+55+76+y+88+54/6

316+y/6=63.6

316+x381.6

x=381.6-316=65.6

2M4 =63

60-62+92+x/4=63

214+x=252

x=252-214

=38

7 0

2 years ago

Read 2 more answers

6x + 2y - 8 = 12x +4y - 16.

Arlecino [84]

Answer:

3x + y = 4

step by step explanation

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2 years ago

By the Interior Angles Theorem, if Angle A is 25° and Angle B is greater than 51° but less than 57°, what are the possible measu

Karo-lina-s [1.5K]

So, if you add 25 and 52 you get 75. All angles of a triangle need to add up to 180. the angle c will be around 105 degrees i assume

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3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

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3 years ago

The problems in the picture

yarga [219]

Answer: a :)

Explanation:

6 0

2 years ago