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yan [13]
3 years ago
9

Find the m∡B to the nearest tenth of a degree if cos B = 0.8926 and ∡B is an acute angle

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

26.8°

Step-by-step explanation:

The cosine of an angle is the ratio of the adjacent side of the triangle in which the angle is formed to the hypotenuses side of the triangle. The cosine of the angle gives the ratio of these sides. However, the arc cosine of the ratio gives the angle measured in degrees.

If cos B = 0.8926

then arc cosine 0.8926  which may be expressed as cos-1 0.8926 will give the value of B.

B = cos-1 0.8926

= 26.8°

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Answer:

a) only extreme values are used in its calculation.

Step-by-step explanation:

In a data set, the range is given by the subtraction of it's highest value by it's lowest value.

The disadvantage is that it gives a high weight to extreme values, not focusing on central values. So the correct answer is given by option a

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Suppose that a police officer measured the speed of cars on a highway for an hour. The average speed of the cars was 72 and the
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djyliett [7]

Answer: Option 3 = 4

Step-by-step explanation: f(x) = 6 - 2x

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8 0
3 years ago
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Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling
arlik [135]

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

  • T = tension in sring and
  • W = weight of particle = mg where
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  • g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

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  • T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

<h3 />

Learn more about tension here:

brainly.com/question/24994188

5 0
2 years ago
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
KATRIN_1 [288]

Answer: x^{\frac{2}{3} }

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

(x^{a})(x^{b}) = x^{a + b} <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

(x^{a})^{b} = x^{(a)(b)} <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

<em />

Let's apply it!

First, let's simplify what's inside the parenthesis.

x^{\frac{4}{3} } x^{\frac{2}{3} } <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

x^{\frac{4}{3} + \frac{2}{3} } = x^{\frac{6}{3} } = x^{2}

Now we have (x^{2})^{\frac{1}{3} }. Let's use the second rule.

(x^{2})^{\frac{1}{3} } = x^{\frac{2}{3} }

Hope this helps! :^)

7 0
3 years ago
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