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yan [13]
3 years ago
9

Find the m∡B to the nearest tenth of a degree if cos B = 0.8926 and ∡B is an acute angle

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

26.8°

Step-by-step explanation:

The cosine of an angle is the ratio of the adjacent side of the triangle in which the angle is formed to the hypotenuses side of the triangle. The cosine of the angle gives the ratio of these sides. However, the arc cosine of the ratio gives the angle measured in degrees.

If cos B = 0.8926

then arc cosine 0.8926  which may be expressed as cos-1 0.8926 will give the value of B.

B = cos-1 0.8926

= 26.8°

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m_a_m_a [10]

Answer:

5 X 4

Step-by-step explanation:

If you plot the dots, youll obviously see a rectangle. The height of the rect. is 4, while the length is 5, so the measurements would be <em>5 x 4.</em>

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<em>Hope this helped!!</em>

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Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region​
yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

<u>Concepts:</u>

Area of Square = s²

  • s = side

Area of Triangle = bh/2

  • b = base
  • h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

<u>Solve:</u>

Question # 16

<em>Step One: Find the total area of two squares</em>

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

<em>Step Two: Find the area of the blank triangle</em>

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

<em>Step Three: Subtract the area of the blank triangle from the total area</em>

Total area = 29

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29 - 7 = 22

-----------------------------------------------------------

Question # 17

<em>Step One: Find the length of PT</em>

Given:

  • PR = 4 cm
  • RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

<em>Step Two: Find the length of S to PT perpendicularly</em>

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Three: Find the area of ΔPST</em>

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Four: Find the length of Q to PT perpendicularly</em>

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Five: Find the area of ΔPQT</em>

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Six: Combine area of two triangles to find the total area</em>

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

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Answer:

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since higest poer is p^3, 3 is higest poer=degree

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