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3 years ago

7

Can someone help me with this math problem? and show me the work? please haha

1 answer:

Licemer1 [7]3 years ago

8 0

I don’t know if you’ll understand the steps

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Solve for x. x +1/2 = 3/4

Alexeev081 [22]

x + 1/2 = 3/4

set denominators equal:

x + 2/4 = 3/4

-2/4 for both sides:

x = 1/4

there you go! hope this helps!

4 0

3 years ago

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1/5k + 15 factor out the coefficient!

skelet666 [1.2K]

1/5k+ 15
= 1/5k+ 15* (5/5) (because 5/5= 1)
= 1/5k+ (15*5)/ 5
= 1/5k+ 75/5
= 1/5k+ 75* (1/5)
= 1/5(k+ 75) (distributive property)

The final answer is 1/5(k+ 75).

3 0

3 years ago

Jack borrows 2000 for 2 years at a rate of 2% how much interest will he owe

neonofarm [45]

2000 x 2 x 0.02 = 80
answer
interest will be $80

7 0

3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

otez555 [7]

Answer:

I needed thisssss ! Thanks for the points and you too<3

Step-by-step explanation:

3 0

3 years ago

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