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dmitriy555 [2]
3 years ago
9

1. Explain the similarities and differences between the graphs of y = 5x and y = 3x. Include domain, range, intervals of increas

e/decrease intercepts, and
asymptotes
2. Explain the similarities and differences between the graphs of y = 4 and y = (2) Include domain, range, intervals of increaseldecrease intercepts, and
asymptotes
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

1. Equal domain, range, interval of increase and lack of asymptotes

The difference is the difference in slope

2. Equal domain, range, no increase or decrease (constant value) and lack of asymptotes

The difference is the difference in the y-intercept

Step-by-step explanation:

1. The similarities between the functions, y = 5·x and y = 3·x are;

a. The domain of y = 5·x is the set of all real numbers and the range is (-∞; ∞)

b.There are no critical point and the interval of increase is (-∞; ∞)

There are no asymptotes the line crosses the origin

The x and y intercept are both zero

Similarly, The domain of y = 3·x is the set of all real numbers and the range is (-∞; ∞)

There are no critical point and the interval of increase is (-∞; ∞)

There are no asymptotes the line crosses the origin

The x and y intercept are both zero

The difference between the functions, y = 5·x and y = 3·x is that the slope of y = 5·x is 5 and the slope of y = 3·x is 3

2.

The similarities between the functions, y = 4 and y = (2)  are;

a. The domain of y = 4 is the set of all real numbers (-∞; ∞), \left \{ x\mid x\in R \right \} and the range is {4}

b.There are no critical point and no interval of increase or decrease

There are no asymptotes the line does not cross the origin

There are no x-intercept and y intercept is (0, 4)

Similarly, the domain of y = (2) is the set of all real numbers (-∞; ∞), \left \{ x\mid x\in R \right \} and the range is {2}

There are no critical point and no interval of increase or decrease

There are no asymptotes the line does not cross the origin

There are no x-intercept and y intercept is (0, 2)

The difference between the functions, y = 4 and y = (2) is that the y-intercept of y = 4 is 4 and  the y-intercept of y = (2) is 2

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Answer:

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Step-by-step explanation:

Here, we want to answer yes or no for each of the numbers

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so, 2 is slope and 3 is y intercept; so 3 in y-intercept is (0,3)

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Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

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The green die has faces numbered 1, 2, 3, 4, 4, and 4.

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P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

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The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

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By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

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Answer: x = (cd + by) / a

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1)Multiply by c on both sides to get:
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