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son4ous [18]
3 years ago
10

Find the slope of the line containing the pair points (9,5) (6,4)

Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer:

y=1/3x+2

Step-by-step explanation:

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3x = 6<br><br> Help me p l e a s e
GuDViN [60]

Answer:

x=2

Step-by-step explanation:

have a nice day

3 0
3 years ago
Fill in the table using this function rule y=-6x-2 -1,0,1,5
Sati [7]

Answer:

-1 = 4

0 = -2

1 = -8

5 = -32

Step-by-step explanation:

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8 0
3 years ago
mrs. lbare wrote three decimals on the bored follwed by the two blank spaces. Complete the sequence of numbers
andrew11 [14]
The rest of the sequence might be 10.5, 12.45, 14.10
5 0
3 years ago
A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo
wel

The side lengths of the pool 10 ft and 45 ft.

<u>SOLUTION: </u>

Given, a rectangle swimming pool is 8 feet deep.  

One side of the pool is 4.5 times longer than the other.  

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,  

\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}

On taking square root on both sides we get,

\begin{array}{l}{\rightarrow\sqrt{n^{2}}=\sqrt{100}} \\\\ {\rightarrow n=10 \mathrm{ft}}\end{array}

So, the width will be 4.5 n=4.5 \times 10=45 \mathrm{ft}

5 0
3 years ago
What are the solution(s) to the quadratic equation 40 − x2 = 0? x = ±2 x = ±4 x = ±2 x = ±4
hichkok12 [17]

Answer: x=\±2\sqrt{10}

Step-by-step explanation:

To find the solutions of the quadratic equation given in the problem, you can apply the proccedure shown below:

- Subtract 40 from both sides of the equation.

- Multiply both sides of the equation by -1

- Apply square root to both sides of the equation.

Therefore, by applyin the steps above, you obtain:

40-x^2-40=0-40\\-x^2=-40\\(-1)(-x^2)=(-40)(-1)\\\\x^2=40\\\\\sqrt{x^2}=\±\sqrt{40}\\\\x=\±2\sqrt{10}

3 0
3 years ago
Read 2 more answers
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